有人可以帮助我将旧的PHP登录代码实现到新的登录模板。 我之前尝试过,页面也已加载,但PHP代码没有工作。
旧登录代码
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not enough 'y' observations

所以这是我从互联网上获得的模板的HTML网站。 Full template
<?php
// Include config file
require_once 'config.php';
// Define variables and initialize with empty values
$username = $password = "";
$username_err = $password_err = "";
// Processing form data when form is submitted
if($_SERVER["REQUEST_METHOD"] == "POST"){
// Check if username is empty
if(empty(trim($_POST["username"]))){
$username_err = 'Please enter username.';
} else{
$username = trim($_POST["username"]);
}
// Check if password is empty
if(empty(trim($_POST['password']))){
$password_err = 'Please enter your password.';
} else{
$password = trim($_POST['password']);
}
// Validate credentials
if(empty($username_err) && empty($password_err)){
// Prepare a select statement
$sql = "SELECT username, password FROM users WHERE username = :username";
if($stmt = $pdo->prepare($sql)){
// Bind variables to the prepared statement as parameters
$stmt->bindParam(':username', $param_username, PDO::PARAM_STR);
// Set parameters
$param_username = trim($_POST["username"]);
// Attempt to execute the prepared statement
if($stmt->execute()){
// Check if username exists, if yes then verify password
if($stmt->rowCount() == 1){
if($row = $stmt->fetch()){
$hashed_password = $row['password'];
if(password_verify($password, $hashed_password)){
/* Password is correct, so start a new session and
save the username to the session */
session_start();
$_SESSION['username'] = $username;
header("location: welcome.php");
} else{
// Display an error message if password is not valid
$password_err = 'The password you entered was not valid.';
}
}
} else{
// Display an error message if username doesn't exist
$username_err = 'No account found with that username.';
}
} else{
echo "Oops! Something went wrong. Please try again later.";
}
}
// Close statement
unset($stmt);
}
// Close connection
unset($pdo);
}
?>
<!DOCTYPE html>
<html lang="de">
<head>
<meta charset="UTF-8">
<title>Login</title>
<link rel="stylesheet" type="text/css" href="/css/style.css">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.css">
</head>
<body>
<div class="body"></div>
<div class="grad"></div>
<div class="header">
<div>SWED
<span>Login
</span>
</div>
</div>
<br>
<div class="login">
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<div class="form-group <?php echo (!empty($username_err)) ? 'has-error' : ''; ?>"></div>
<input type="text" name="username" placeholder="username" class="form-control" value="<?php echo $username; ?>">
<span class="help-block" style="color: red;"><?php echo $username_err; ?></span>
<div class="form-group <?php echo (!empty($password_err)) ? 'has-error' : ''; ?>"></div>
<input type="password" placeholder="password" name="password" class="form-control">
<span class="help-block" style="color: red;"><?php echo $password_err; ?></span>
<input type="submit" class="btn btn-primary" value="Submit">
<p style="color: grey;">Don't have an account? <a href="register.php" style="text-decoration: none; color: white;">Sign up</a></p>
</form>
</div>
</body>
</html>
&#13;
我只是学习php,所以请原谅我,如果它应该是一个非常简单的错误。 对不起我的英语不好,我希望它不是太重要。 感谢您的帮助
答案 0 :(得分:0)
表单元素必须具有动作属性,该属性具有到php页面的链接
像:
<form class="login100-form validate-form" action="login.php" method="POST">
并且输入元素的名称必须与$_POST['username'] & $_POST['password']
相同
在您的HTML模板中输入的名称与php变量不匹配
它必须像
<input class="input100" type="text" name="username">
<input class="input100" type="password" name="password">