我正在使用mysql，jpa开发一个spring boot库应用程序。数据库表由以下列组成：bookName，author，copiesTotal，copiesAvailable，people。问题出在JSONObject列“people”上。我想使用“人物”栏来存储借阅某本书的人的详细信息。
“people”栏目例如：{“john”：“9876543210”，“mark”：“0123456789”}
我想使用任何注释或代码中是否有错误？
这是我的代码。
Book.java
Caused by: org.hibernate.MappingException: Could not determine type for: org.json.JSONObject, at table: book, for columns: [org.hibernate.mapping.Column(people)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:431) ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:398) ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
at org.hibernate.mapping.Property.isValid(Property.java:225) ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:595) ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
at org.hibernate.mapping.RootClass.validate(RootClass.java:265) ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
at org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:329) ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:443) ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:879) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
... 23 common frames omitted
CONSOLE：
<h2>Los ingredientes</h2>
<ul>
<li>500 g de queso feta</li>
<li>½ cucharadita de pimienta negra</li>
<li>1 cucharadita de pimienta rosada</li>
<li>3 ramas pequeñas de romero</li>
<li>aceite de oliva </li>
</ul>
<h2>La preparación</h2>
<p>Corta el queso feta en dados y déjalos reposar sobre papel absorbente.</p>