我有以下两种方法,
initialJob();
otherJobs();
其他工作只需要在初始工作完成后启动。
这是最初的工作方法。
private void initialJob(){
JobDetail jobDetail = JobBuilder.newJob(RestTriggerForQuartzJobs.class)
.withIdentity("INITIAL_JOB_NAME", TRIGGER_GROUP)
.usingJobData("PARAM", "")
.build();
Trigger trigger = TriggerBuilder.newTrigger().forJob(jobDetail).startNow().build();
scheduler.scheduleJob(jobDetail, trigger);
}
我在这里检查初始工作是否完成。如果没有,则递归调用相同的方法直到完成
private void otherJobs(){
if(isJobComplete("INITIAL_JOB_NAME")){
JobDetail jobDetail = JobBuilder.newJob(RestTriggerForQuartzJobs.class)
.withIdentity("JOB_NAME", TRIGGER_GROUP)
.usingJobData("PARAM", "")
.build();
Trigger trigger = TriggerBuilder.newTrigger().forJob(jobDetail).startNow().build();
scheduler.scheduleJob(jobDetail, trigger);
}else{
otherJobs();
}
}
在isComplete方法中,对于JobDetail jobDetail = scheduler.getJobDetail(jobKey),jobDetail变为null,尽管我可以在quartz触发器表中看到DEFAULT.INITIAL_JOB_NAME。
private Boolean isJobComplete(String jobName) throws SchedulerException {
JobKey jobKey = new JobKey(jobName);
JobDetail jobDetail = scheduler.getJobDetail(jobKey);
List<? extends Trigger> triggers = scheduler.getTriggersOfJob(jobDetail.getKey());
for (Trigger trigger : triggers) {
TriggerState triggerState = scheduler.getTriggerState(trigger.getKey());
if (TriggerState.COMPLETE.equals(triggerState)) {
return true;
}
}
return false;
}
答案 0 :(得分:1)
方法scheduler.getJobDetail(jobKey)
返回null,因为JobKey
由名称和组组成,以便唯一地标识作业。
这意味着您必须使用名称和组发起JobKey
:
private Boolean isJobComplete(String jobName) throws SchedulerException {
JobKey jobKey = new JobKey(jobName, TRIGGER_GROUP);
JobDetail jobDetail = scheduler.getJobDetail(jobKey);
...
顺便提一下:方法otherJobs
以递归方式调用未定义的时间可能会导致StackOverflowError
。也许listeners对您的用例很有用。