Question

给定一个结构列表，有没有办法可以根据预定的指标（比如游戏难度）改变概率属性？该概率属性是随机选择房间的概率。

我当前的概率属性已设置，是一个不断更新的噩梦。既然我想引入一个可以调整这些值的外部设置，我需要完全重新设计这个概率的设置方式。请参阅下面的当前设置：

defmodule Sandbox do
  defstruct description: nil, chance: nil

  def all, do: [
    %Sandbox{
      description: "Description 1",
      chance: 1..40
    },
    %Sandbox{
      description: "Description 2",
      chance: 41..60
    },
    %Sandbox{
      description: "Description 3",
      chance: 61..100
    },
  ]

  def random do
    rand = Enum.random(1..100)
    Enum.find(all(), fn %{chance: chance} -> rand in chance end)
  end
end

问题

如何将当前设置转换为调整struct属性的设置＆＃34; chance＆＃34;根据预定的设置（game_difficulty = easy，medium或hard）并返回随机选择的Sandbox？

Answer 1

我会在每个结构中存储每个难度的概率，然后让random接受难度级别：

defmodule Sandbox do
  defstruct description: nil, easy: nil, medium: nil, hard: nil

  def all, do: [
    %Sandbox{
      description: "Description 1",
      easy: 1..40,
      medium: 1..50,
      hard: 1..60,
    },
    %Sandbox{
      description: "Description 2",
      easy: 41..60,
      medium: 51..80,
      hard: 61..90,
    },
    %Sandbox{
      description: "Description 3",
      easy: 61..100,
      medium: 81..100,
      hard: 91..100,
    },
  ]

  def random(difficulty) do
    rand = Enum.random(1..100)
    Enum.find(all(), fn s -> rand in Map.get(s, difficulty) end)
  end
end

IO.inspect Sandbox.random(:easy)
IO.inspect Sandbox.random(:medium)
IO.inspect Sandbox.random(:hard)

Answer 2

我会根据难度选择百分比机会来选择房间：

defmodule Sandbox do
  defstruct description: nil, chance: nil

  def all, do: [
    %Sandbox{
      description: "Description 1",
      chance: %{easy: 75, medium: 40, hard: 10}
    },
    %Sandbox{
      description: "Description 2",
      chance: %{easy: 100, medium: 100, hard: 100}
    },
    %Sandbox{
      description: "Description 3",
      chance: %{easy: 100, medium: 50, hard: 10}
    },
  ]

  def random_by_difficulty(rooms, difficulty) do
    mark = Enum.random(1..100)

    rooms
    |> Enum.filter(fn room -> room.chance[difficulty] >= mark end)
    |> Enum.random()
  end
end

Elixir：可选择的概率结构属性

2 个答案: