示例:
输入:
{"Contact Title": "Owner Name"}
预期产出:
{"ContactTitle": "Owner Name"}
答案 0 :(得分:0)
使用json object_hooks(支持嵌套字典)的示例:
In [1]: import json
...:
...: example_dict = {'ke y1': 'value1',
...: 'ke y2': 'value2',
...: 'k ey3': {'key3a': 'value3a'},
...: 'key 4': {'key 4a': {'key4a a': {'key 4 4 4 44': 'value44 4 44'},
...: 'key4 ab': 'value 4ab',
...: 'key4ac': 'va lue4ac'},
...: 'k ey4b': 'valu e4b'}}
...:
...: def remove_spaces(obj):
...: for key in obj.keys():
...: new_key = key.replace(" ","")
...: if new_key != key:
...: obj[new_key] = obj[key]
...: del obj[key]
...: return obj
...:
...: new_json = json.loads(json.dumps(example_dict), object_hook=remove_spaces)
...:
...: new_json
...:
Out[1]:
{u'key1': u'value1',
u'key2': u'value2',
u'key3': {u'key3a': u'value3a'},
u'key4': {u'key4a': {u'key4aa': {u'key44444': u'value44 4 44'},
u'key4ab': u'value 4ab',
u'key4ac': u'va lue4ac'},
u'key4b': u'valu e4b'}}
还有另一种方法(只要你不超过递归深度就更好):
In [2]: def dict_key_unspacer(d):
...: new = {}
...: for k, v in d.iteritems():
...: if isinstance(v, dict):
...: v = print_dict(v)
...: new[k.replace(' ', '')] = v
...: return new
...:
...: result_dict = dict_key_unspacer(example_dict)
...:
...: result_dict
...:
Out[2]:
{'key1': 'value1',
'key2': 'value2',
'key3': {'key3a': 'value3a'},
'key4': {'key4a': {'key4aa': {'key44444': 'value44 4 44'},
'key4ab': 'value 4ab',
'key4ac': 'va lue4ac'},
'key4b': 'valu e4b'}}
答案 1 :(得分:0)
谢谢你的建议,我在一行中尝试了一些正则表达式并且工作正常,但我看到输出中的顺序发生了变化。
input = [{ “Id”:“ALFKI”, “联系人姓名”:“Maria Anders”, “联系人标题”:“销售代表”, “城市”:“柏林”, “滑块”:10 },{ “Id”:“ANATR”, “联系人姓名”:“Ana Trujillo”, “联系人标题”:“所有者”, “城市”:“墨西哥D.F.”, “滑块”:5 }]
new_json =(re.sub(r'\ s(?= \ w +“:)',”“,str(json.dumps(input))))
输出= [ { “ContactName”:“Maria Anders”, “ContactTitle”:“销售代表”, “Id”:“ALFKI”, “滑块”:10, “城市”:“柏林” }, { “ContactName”:“Ana Trujillo”, “ContactTitle”:“所有者”, “Id”:“ANATR”, “滑块”:5, “城市”:“墨西哥D.F.” } ]