Question

我一直在线上发现错误：

state = node["state"]

然而这有效：

print node["state"]

获得我得到的类型时：

print(type(node))
--><type 'dict'>
--><type 'tuple'>

以下是完整代码：

explored = dict()
state = problem.getStartState()
frontier = util.Stack()

node = {}
node["parent"] = None
node["action"] = None
node["state"] = state

frontier.push(node)

while not frontier.isEmpty():

  node = frontier.pop()
  state = node["state"]

  if problem.isGoalState(state) == True:
        break

  if state in explored:
       continue

  explored[state] = True




 class Stack:

   def __init__(self):
   self.list = []

   def push(self,item):
     self.list.append(item)

   def pop(self):
     return self.list.pop()

Answer 1

看起来你真的有一个元组，而不是你期望的字典。

class Stack:
    def __init__(self):
        self.list = []

    def push(self,item):
        self.list.append(item)

    def pop(self):
        return self.list.pop()

    def isEmpty(self):
        return len(self.list) == 0

state = 'blah'
explored = dict()
frontier = Stack()

node = {}
node["parent"] = None
node["action"] = None
node["state"] = state

frontier.push(node)

while not frontier.isEmpty():

  node = frontier.pop()
  print(type(node)) # <--- NEW
  state = node["state"]

  #if problem.isGoalState(state) == True:
        #break

  #if state in explored:
       #continue

  explored[state] = True

此代码仅返回<class 'dict'> - 因此列表中可能存在您不知道的内容

元组索引必须是整数，而不是str

1 个答案: