选择每个职业都有高薪的所有员工

Question

我有这张桌子。我想以最高薪水选择每个职业的所有员工。

我尝试了一切，但似乎没有任何工作。 以下查询结果错误。

SELECT * FROM Employee WHERE EmployeeID IN (
SELECT EmployeeID FROM Employee  HAVING MAX(Salary) = Salary GROUP BY Profession)

Answer 1

您可以使用ROW_NUMBER窗口功能

SELECT *
FROM   (SELECT *,
               Row_number()OVER (PARTITION BY Profession ORDER BY Salary DESC) rn
        FROM   Employee) a
WHERE  rn = 1 

注意：当一个职业的最高薪水达到平局时，如果您需要领带记录，则只返回一个，然后使用DENSE_RANK

SELECT *
FROM   (SELECT *,
               Dense_rank()OVER (PARTITION BY Profession ORDER BY Salary DESC) rn
        FROM   Employee) a
WHERE  rn = 1 

如果你想修复你的子查询然后（将返回平局记录）

SELECT *
FROM   Employee e1
WHERE  Salary = (SELECT Max(Salary)
                 FROM   Employee e2
                 WHERE  e1.Profession = e2.Profession) 

或

SELECT *
FROM   Employee e1
WHERE  EXISTS (SELECT 1
               FROM   Employee e2
               WHERE  e1.Profession = e2.Profession
               HAVING Max(Salary) = e1.Salary) 

Answer 2

SELECT * 
FROM (
      SELECT * 
           , ROW_NUMBER() OVER (PARTITION BY Profession ORDER BY Salary DESC) rn 
      FROM Employee
      ) x
WHERE x.rn = 1

Answer 3

尝试这个简单的查询！

SELECT 
       EmployeeID              ,
       EmployeeName            ,
       Profession              ,
       max(Salary)   AS 'Salary'
FROM 
       Employee
GROUP BY 
       Profession

Answer 4

SELECT *
FROM employees 
WHERE salary IN (SELECT MAX(salary)
                 FROM Employees
                 GROUP BY Profession)