Question

有可能简化这个吗？也许两者相结合？教我干燥的方法： - \

o = old_last_result
if o == 7:
    old_last_result_msg = result_7
elif o == 12:
    old_last_result_msg = result_12
elif o == 23:
    old_last_result_msg = result_23
elif o == 24:
    old_last_result_msg = result_24
elif o == 103:
    old_last_result_msg = result_103
elif o == 1000:
    old_last_result_msg = result_1000
else:
    old_last_result_msg = "Error code: #%s" % old_last_result

n = new_last_result
if n == 7:
    new_last_result_msg = result_7
elif n == 12:
    new_last_result_msg = result_12
elif n == 23:
    new_last_result_msg = result_23
elif n == 24:
    new_last_result_msg = result_24
elif n == 103:
    new_last_result_msg = result_103
elif n == 1000:
    new_last_result_msg = result_1000
else:
    new_last_result_msg = "Error code: #%s" % new_last_result

Answer 1

result_msgs = {
  7: result_7,
  12: result_12,
   ...
}

old_last_result_msg = result_msgs.get(old_last_result,
  "Error code: #%s" % old_last_result)
new_last_result_msg = result_msgs.get(new_last_result,
  "Error code: #%s" % new_last_result)

Answer 2

您可以使用词典：

results = {7: result_7, ..., 1000: result_100}
old_last_result_msg = results.get(o, "Error code: #%s" % old_last_result)

Answer 3

您似乎将数字代码映射到字符串消息。使用词典！观察：

_result_msg = {
    7: result_7,
    12: result_12,
    # ... etc
}

o = old_last_result
try:
    old_last_result_msg = _result_msg[o]
except KeyError:
    old_last_result_msg = 'Error code: #%s' % o

Answer 4

eval对你来说可能很有意思......

i = 7
result_7 = 'foo'
print eval('result_%s' % i)
> foo

Answer 5

您可以使用内置的locals（）或globals（）来构造变量，如：

var res = "result_%d"%o
if res in locals(): old_last_result_msg = locals()[res]
else:
    if res in globals(): old_last_result_msg = globals()[res]
    else: raise Exception("unexpected result:%s"%res)

在Python中，我可以在一个条件中处理两个变量吗？

5 个答案: