如何在python3中访问PHP函数

Question

我正在尝试在PHP中将python3中的import subprocess subprocess.call(["php", "./php1.php"]) script_response = subprocess.check_output(["php", "./php1.php"]) 函数作为php1.php访问Traceback (most recent call last): File "test3.py", line 7, in <module> subprocess.call(["php", "./php1.php"]) File "/usr/lib/python3.5/subprocess.py", line 557, in call with Popen(*popenargs, **kwargs) as p: File "/usr/lib/python3.5/subprocess.py", line 947, in __init__ restore_signals, start_new_session) File "/usr/lib/python3.5/subprocess.py", line 1551, in _execute_child raise child_exception_type(errno_num, err_msg) FileNotFoundError: [Errno 2] No such file or directory: 'php' 。我看到了post

但由于我没有足够的声誉对此发表评论。我在这里发布我的查询。

这是我在这里尝试的代码：

Get-ChildItem -Path $input -Filter '*.dll' | ForEach-Object {
    $assembly = [System.Reflection.Assembly]::Load([IO.File]::ReadAllBytes($_.FullName))
    Write-Host $assembly.FullName
}

并收到此错误。

||

我想我错过了一些基本的东西。请帮帮我。