Question

我有一个包含多个值的csv文件：字符串，日期，数字...... 宏（Excel）将csv数据导入Excel工作表，一切顺利，但...... 在csv文件中，我有一个日期列：“8/1/2018”（其中5表示日，1表示月份。格式：d / M / Y），但是当我转到导入的数据时，我看到了日期如：“1/8/2018”（注意日期和月份置换）。这很烦人，因为我的区域窗口配置指定了格式：d / M / Y. 在这里你可以看到所有发生的行：错误的日期转换：

如何以正确的格式导入日期数据？也许是Sheet的一些dateFormat？

修改这是打开文件的代码：

Sub ImportFile()
Dim sPath As String
'Below we assume that the file, csvtest.csv,
'is in the same folder as the workbook. If
'you want something more flexible, you can
'use Application.GetOpenFilename to get a
'file open dialogue that returns the name
'of the selected file.
'On the page Fast text file import
'I show how to do that - just replace the
'file pattern "txt" with "csv".
sPath = ThisWorkbook.Path & "\2018w02_wbt_exito.csv"

'Procedure call. Semicolon is defined as separator,
'and data is to be inserted on "Sheet2".
'Of course you could also read the separator
'and sheet name from the worksheet or an input
'box. There are several options.
copyDataFromCsvFileToSheet sPath, ";", """", "Hoja1"

End Sub
'**************************************************************
Private Sub copyDataFromCsvFileToSheet(parFileName As String, _
parDelimiter As String, parExcludeCharacter As String, parSheetName As String)

Dim Data As Variant  'Array for the file values

'Function call - the file is read into the array
Data = getDataFromFile(parFileName, parDelimiter, parExcludeCharacter)

'If the array isn't empty it is inserted into
'the sheet in one swift operation.
If Not isArrayEmpty(Data) Then
  'If you want to operate directly on the array,
  'you can leave out the following lines.
  With Sheets(parSheetName)
    'Delete any old content
    ' .Cells.ClearContents
    'A range gets the same dimensions as the array
    'and the array values are inserted in one operation.
    .Cells(2, 1).Resize(UBound(Data, 1), UBound(Data, 2)) = Data
  End With
End If
End Sub
'**************************************************************
Public Function isArrayEmpty(parArray As Variant) As Boolean
'Returns False if not an array or a dynamic array
'that hasn't been initialised (ReDim) or
'deleted (Erase).

If IsArray(parArray) = False Then isArrayEmpty = True
On Error Resume Next
If UBound(parArray) < LBound(parArray) Then
   isArrayEmpty = True
   Exit Function
Else
   isArrayEmpty = False
End If

End Function
'**************************************************************
Private Function getDataFromFile(parFileName As String, _
parDelimiter As String, _
Optional parExcludeCharacter As String = "") As Variant
'parFileName is the delimited file (csv, txt ...)
'parDelimiter is the separator, e.g. semicolon.
'The function returns an empty array, if the file
'is empty or cannot be opened.
'Number of columns is based on the line with most
'columns and not the first line.
'parExcludeCharacter: Some csv files have strings in
'quotations marks ("ABC"), and if parExcludeCharacter = """"
'quotation marks are removed.

Dim locLinesList() As Variant 'Array
Dim locData As Variant        'Array
Dim i As Long                 'Counter
Dim j As Long                 'Counter
Dim locNumRows As Long        'Nb of rows
Dim locNumCols As Long        'Nb of columns
Dim fso As Variant            'File system object
Dim ts As Variant             'File variable
Const REDIM_STEP = 10000      'Constant

'If this fails you need to reference Microsoft Scripting Runtime.
'You select this in "Tools" (VBA editor menu).
Set fso = CreateObject("Scripting.FileSystemObject")

On Error GoTo error_open_file
'Sets ts = the file
Set ts = fso.OpenTextFile(parFileName)
On Error GoTo unhandled_error

'Initialise the array
ReDim locLinesList(1 To 1) As Variant
i = 0
'Loops through the file, counts the number of lines (rows)
'and finds the highest number of columns.
Do While Not ts.AtEndOfStream
  'If the row number Mod 10000 = 0
  'we redimension the array.
  If i Mod REDIM_STEP = 0 Then
    ReDim Preserve locLinesList _
    (1 To UBound(locLinesList, 1) + REDIM_STEP) As Variant
  End If
  locLinesList(i + 1) = Split(ts.ReadLine, parDelimiter)
  j = UBound(locLinesList(i + 1), 1) 'Nb of columns in present row
  'If the number of columns is then highest so far.
  'the new number is saved.
  If locNumCols < j Then locNumCols = j
  i = i + 1
Loop

ts.Close 'Close file

locNumRows = i

'If number of rows is zero
If locNumRows = 0 Then Exit Function

ReDim locData(1 To locNumRows, 1 To locNumCols + 1) As Variant

'Copies the file values into an array.
'If parExcludeCharacter has a value,
'the characters are removed.
If parExcludeCharacter <> "" Then
  For i = 1 To locNumRows
    For j = 0 To UBound(locLinesList(i), 1)
      If Left(locLinesList(i)(j), 1) = parExcludeCharacter Then
        If Right(locLinesList(i)(j), 1) = parExcludeCharacter Then
          locLinesList(i)(j) = _
          Mid(locLinesList(i)(j), 2, Len(locLinesList(i)(j)) - 2)
        Else
          locLinesList(i)(j) = _
          Right(locLinesList(i)(j), Len(locLinesList(i)(j)) - 1)
        End If
      ElseIf Right(locLinesList(i)(j), 1) = parExcludeCharacter Then
        locLinesList(i)(j) = _
        Left(locLinesList(i)(j), Len(locLinesList(i)(j)) - 1)
      End If
      locData(i, j + 1) = locLinesList(i)(j)
    Next j
  Next i
Else
  For i = 1 To locNumRows
    For j = 0 To UBound(locLinesList(i), 1)
      locData(i, j + 1) = locLinesList(i)(j)
    Next j
  Next i
End If

getDataFromFile = locData

Exit Function

error_open_file:  'Returns empty Variant
unhandled_error:  'Returns empty Variant

End Function

Answer 1

如果您想使用FileSystemObject获取数据，则需要先将Data变量中的每个日期项转换为“实际日期”，然后再将其写入工作表。

正如截图所示，它是一个字符串，正如您所发现的那样，写入工作表时的转换是不可靠的。

转换它的一种方法。

Dim V As Variant, i As Long
For i = LBound(Data) To UBound(Data)
    V = Split(Data(i, 3), "/")

    'test for proper date
    If UBound(V) = 2 Then _
        Data(i, 3) = DateSerial(V(2), V(1), V(0))
Next i

可能更容易导入数据而不是使用FSO

将数据从csv复制到Sheet时日期格式更改

1 个答案: