Question

typedef struct secinfo_t {
    struct secinfo_t*   next; /* NULL for no next section */
    const char*     name; /* nul-terminated section name */
    void*       addr; /* Address of section in memory */
    uint32_t        size; /* length of section (bytes) */
    uint32_t        flags; /* flags, see below */
    struct secinfo_t*   romcopyof; /* this section is a ROM copy of 'romcopyof' */enter code here

 /* Future fields go here */
} *secinfo_ptr;

什么是＆＃34; next＆＃34;和＆＃34; romcopyof＆＃34;在结构上使用类型指针创建的成员？我不明白的问题是我所创建的成员的结构类型是什么？有人可以更详细地解释一下吗？

Answer 1

typedef struct secinfo_t {
struct secinfo_t*   next; /* NULL for no next section */
const char*     name; /* nul-terminated section name */
void*       addr; /* Address of section in memory */
uint32_t        size; /* length of section (bytes) */
uint32_t        flags; /* flags, see below */
struct secinfo_t*   romcopyof; /* this section is a ROM copy of     'romcopyof' */enter code here

} *secinfo_ptr;

结构中的struct secinfo_t* next;是结构自身的引用，当结构对象与其他'实例'相关联时使用本身，即这通常用于（二进制）树或链接列表中的节点：

typedef struct Node Node;

struct Node
{
  int value;
  Node *next;
  Node *prev;
};

来源：How to define a typedef struct containing pointers to itself?

有关如何使用此编码结构的示例，请参阅http://www.learn-c.org/en/Linked_lists和https://www.geeksforgeeks.org/binary-tree-set-1-introduction/

struct secinfo_t* romcopyof;是指向secinfo_t的ROM副本的指针，ROM是在EEPROM中或硬盘上而不是在执行代码的RAM中...

究竟是什么意味着结构上的指针被创建成相同的结构？

1 个答案: