Question

 $scope.Array1= [{
      Name: 'Alzheimers',
      Value: 1,
      Selected: false
  }, {
      Name: 'Arthritis',
      Value: 2,
      Selected: false
  },{
      Name: 'Cancer',
      Value: 3,
      Selected: false
  }{
      Name: 'Cellulitis',
      Value: 4,
      Selected: false
  }
  ];

$scope.Array2=[1,3];

我希望结果像

$scope.Array1= [{
          Name: 'Alzheimers',
          Value: 1,
          Selected: true
      }, {
          Name: 'Arthritis',
          Value: 2,
          Selected: false
      },{
          Name: 'Cancer',
          Value: 3,
          Selected: true
      }{
          Name: 'Cellulitis',
          Value: 4,
          Selected: false
      }
      ];

selected对象变量(Alzheimers,Cancer)从Array2更新为true？ 如果你提出没有循环的建议，那对我来说会很棒。

Answer 1

使用Array#forEach对array1进行迭代，检查Value中是否包含Array2，并将结果分配给Selected属性。该解决方案将改变原始对象。

＆＃13;

const array1 = [{"Name":"Alzheimers","Value":1,"Selected":false},{"Name":"Arthritis","Value":2,"Selected":false},{"Name":"Cancer","Value":3,"Selected":false},{"Name":"Cellulitis","Value":4,"Selected":false}];

const array2 = [1, 3];

array1.forEach((o) => o.Selected = array2.includes(o.Value));

console.log(array1);

＆＃13;

如果您想要一个包含新对象的新数组，请使用Array#map，使用Object＃assign。

＆＃13;

let array1 = [{"Name":"Alzheimers","Value":1,"Selected":false},{"Name":"Arthritis","Value":2,"Selected":false},{"Name":"Cancer","Value":3,"Selected":false},{"Name":"Cellulitis","Value":4,"Selected":false}];

const array2 = [1, 3];

array1 = array1.map((o) => array2.includes(o.Value) ? Object.assign({}, o, {
  Selected: true
}) : o);

console.log(array1);

＆＃13;

Answer 2

您可以使用forEach

＆＃13;

let array1 = 
[
	{"Name":"Alzheimers","Value":1,"Selected":false},
	{"Name":"Arthritis","Value":2,"Selected":true},
	{"Name":"Cancer","Value":3,"Selected":false},
	{"Name":"Cellulitis","Value":4,"Selected":false}
];
let array2 = [1, 3];
array1.forEach(x => x.Selected = array2.indexOf(x.Value) != -1);
console.log(array1);

＆＃13;

从另一个数组更新数组对象

2 个答案: