我想从this获取公司的所有社交链接。做的时候
summary_div.find("div", {'class': "cp-summary__social-links"})
我收到了这个
<div class="cp-summary__social-links">
<div data-integration-name="react-component" data-payload='{"props":
{"links":[{"url":"http://www.snapdeal.com?utm_source=craft.co","icon":"web","label":"Website"},
{"url":"http://www.linkedin.com/company/snapdeal?utm_source=craft.co","icon":"linkedin","label":"LinkedIn"},
{"url":"https://instagram.com/snapdeal/?utm_source=craft.co","icon":"instagram","label":"Instagram"},
{"url":"https://www.facebook.com/Snapdeal?utm_source=craft.co","icon":"facebook","label":"Facebook"},
{"url":"https://www.crunchbase.com/organization/snapdeal?utm_source=craft.co","icon":"cb","label":"CrunchBase"},
{"url":"https://www.youtube.com/user/snapdeal?utm_source=craft.co","icon":"youtube","label":"YouTube"},
{"url":"https://twitter.com/snapdeal?utm_source=craft.co","icon":"twitter","label":"Twitter"}],
"companyName":"Snapdeal"},"name":"CompanyLinks"}' data-rwr-element="true"></div></div>
我也试过让cp-summary__social-links的孩子成为我想要的孩子，然后找到所有a标签以获取所有链接。这也行不通。
任何想法，怎么做？
更新：正如Sraw建议的那样，我设法通过这样做来获取所有网址。
urls = []
social_link = summary_div.find("div", {'class': "cp-summary__social-links"}).find("div", {"data-integration-name": "react-component"})
json_text = json.loads(social_link["data-payload"])
for link in json_text['props']['links']:
urls.append(link['url'])
提前致谢。