Question

我试图策划两件事：

MD，VA和DC的县
Lats / Longs用于在该区域内安装房源（最贵的是某种颜色）另一种颜色最便宜）

但是，我在第1部分遇到问题，似乎无法在没有收到错误消息的情况下绘制县：

＆＃34; Javascript错误添加输出！错误：渲染Bokeh模型时出错：找不到ID为：xxxxxxxxxxx的标记有关更多详细信息，请参阅浏览器Javascript控制台。＆＃34;

其中xxxxx是数字

from bokeh.io import show
from bokeh.models import (
ColumnDataSource,
HoverTool,
LogColorMapper)
from bokeh.palettes import Viridis6 as palette
from bokeh.plotting import figure

from bokeh.sampledata.us_counties import data as counties
from bokeh.sampledata.unemployment import data as unemployment

palette.reverse()

va_counties = {
    code: county for code, county in counties.items() if county["state"] == "va"
}
md_counties = {
    code: county for code, county in counties.items() if county["state"] == "md"
}
dc_counties = {
    code: county for code, county in counties.items() if county["state"] == "dc"
}

va_county_xs = [county["lons"] for county in va_counties.values()]
va_county_ys = [county["lats"] for county in va_counties.values()]

md_county_xs = [county["lons"] for county in md_counties.values()]
md_county_ys = [county["lats"] for county in md_counties.values()]

dc_county_xs = [county["lons"] for county in dc_counties.values()]
dc_county_ys = [county["lats"] for county in dc_counties.values()]

va_county_names = [county['name'] for county in va_counties.values()]
md_county_names = [county['name'] for county in md_counties.values()]
dc_county_names = [county['name'] for county in dc_counties.values()]


#county_rates = [unemployment[county_id] for county_id in counties]
color_mapper = LogColorMapper(palette=palette)

va_source = ColumnDataSource(data=dict(
    x=va_county_xs,
    y=va_county_ys,
    name=va_county_names,
))

md_source = ColumnDataSource(data=dict(
     x=md_county_xs,
y=md_county_ys,
name=md_county_names,
))

dc_source = ColumnDataSource(data=dict(
    x=dc_county_xs,
    y=dc_county_ys,
    name=dc_county_names,
))

TOOLS = "pan,wheel_zoom,reset,hover,save"

va = figure(
    title="Texas Unemployment, 2009", tools=TOOLS,
    x_axis_location=None, y_axis_location=None
)
va.grid.grid_line_color = None

md = figure(
    title="Texas Unemployment, 2009", tools=TOOLS,
    x_axis_location=None, y_axis_location=None
)
md.grid.grid_line_color = None

dc = figure(
    title="Texas Unemployment, 2009", tools=TOOLS,
    x_axis_location=None, y_axis_location=None
)
dc.grid.grid_line_color = None

va.patches('x', 'y', source=va_source,
          fill_color={'field': 'rate', 'transform': color_mapper},
          fill_alpha=0.7, line_color="white", line_width=0.5)
md.patches('x', 'y', source=md_source,
          fill_color={'field': 'rate', 'transform': color_mapper},
          fill_alpha=0.7, line_color="white", line_width=0.5)
dc.patches('x', 'y', source=dc_source,
          fill_color={'field': 'rate', 'transform': color_mapper},
          fill_alpha=0.7, line_color="white", line_width=0.5)

hover = p.select_one(HoverTool)
hover.point_policy = "follow_mouse"
hover.tooltips = [
    ("Name", "@name"),
    ("(Long, Lat)", "($x, $y)"),
]

show(va)
show(md)
show(dc)

Answer 1

Bokeh保留了一份隐含的＆＃34;当前文件＆＃34;默认情况下，您所做的一切都会添加到其中。这使得生成一个HTML文件的脚本非常简单，特别是在Jupyter笔记本中使用更加简单和透明。一般来说，这是一个净积极的，但它确实使某些其他使用模式需要稍微冗长。特别是在您进行多次show调用的情况下，每次调用show都会获得相同的文档，这可能不是您想要的。解决方案是按顺序创建和显示每个图，并在其间调用reset_output。此外，您确实需要使用output_file为每个单独的输出指定唯一的文件名。这是一个小例子：

from bokeh.io import output_file, reset_output, show
from bokeh.plotting import figure

# create and show one figure
p1 = figure(title="plot 1")
p1.circle([1,2,3], [4,6,5])

output_file("p1.html")
show(p1)

# clear out the "current document"
reset_output()

# create and show another figure
p2 = figure(title="plot 2")
p2.circle([1,2,3], [8,6,7])

output_file("p2.html")
show(p2)

通过自己明确管理Bokeh Document对象还有其他方法可以做到这一点，但我可能会说这是最简单的入门方法。

绘制多个状态散景

1 个答案: