我今天一直在做一个小项目，在StackOverflow和其他地方寻找答案之后，我已经遇到了障碍。
我一直在尝试用Java创建一个自己冒险的冒险游戏，我首先要创建一个使用三个特征（名称，种族，性别）的角色。我计划使用这些来容纳故事中的分支。
问题在于我没有得到我正在寻找的结果。目前，我已经让我的代码工作了，打印声明显示了播放器的选择。
//list out character description
System.out.println("You are " + Name + ", a " + characterGender + " " +
characterRace + ".");
我让它正常工作，直到我尝试对输入的输入执行测试，以根除无效的条目。我试图使用do-while循环和try-catch语句，但它只是向前运行到下一个选项，无论是否有有效输入。
我希望实施的一般想法是：
显示输入选项
检查输入以确认其有效
如果输入无效，请重新尝试检查其他输入
如果输入有效，请转到下一个问题
//create test to verify validity of race selection
boolean raceBoolean;
if (raceInt < 0 || raceInt > 4) {
raceBoolean = true;
try {
do {
//selection list that defines options
if (raceInt == 1)
characterRace = "human";
else if (raceInt == 2)
characterRace = "elf";
else if (raceInt == 3)
characterRace = "orc";
else if (raceInt == 4)
characterRace = "undead";
}
while (raceBoolean = false);
System.out.println("Nice try. Enter a valid number for one of the four races!");
}
finally {
}
老实说，我不知所措。我知道这很简单，但我试图自学。我感谢您提供的任何帮助。其他主题并不是非常有用，因为它们首先没有提供很多背景信息。
提前谢谢你。我老老实实地想要学习如何正确地做到这一点。
以下完整代码：
import java.util.Scanner;
public class Adventure {
public static void main(String[] args) {
// TODO Auto-generated method stub
//insert input tool
Scanner input = new Scanner(System.in);
//create inventory object for gold and items
int gold = 10;
//create health points object
//address player with greeting
System.out.println("Welcome to your adventure!");
//ask for character name, race, and gender
System.out.println("What will your adventurer's name be?");
String Name = input.nextLine();
System.out.println("What will your adventurer's race be?");
System.out.println("1. Human");
System.out.println("2. Elf");
System.out.println("3. Orc");
System.out.println("4. Undead");
int raceInt = input.nextInt();
String characterRace = "";
//create test to verify validity of race selection
boolean raceBoolean;
if (raceInt < 0 || raceInt > 4) {
raceBoolean = true;
try {
do {
//selection list that defines options
if (raceInt == 1)
characterRace = "human";
else if (raceInt == 2)
characterRace = "elf";
else if (raceInt == 3)
characterRace = "orc";
else if (raceInt == 4)
characterRace = "undead";
}
while (raceBoolean = false);
System.out.println("Nice try. Enter a valid number for one of the four races!");
}
finally {
}
}
//ask for character gender
System.out.println("What will your adventurer's gender be?");
System.out.println("1. Male");
System.out.println("2. Female");
int genderInt = input.nextInt();
String characterGender = "";
if (genderInt == 1)
characterGender = "male";
else if (genderInt == 2)
characterGender = "female";
//list out character description
System.out.println("You are " + Name + ", a " + characterGender + " " + characterRace + ".");
//introduce player to adventure with different introductions for different races
System.out.print("You came to Glassolin with only ten gold pieces to your name. ");
if (characterRace == "human")
System.out.print("Glassolin is home to many humans; some from the far reaches of the realm. You feel right at home, more or less,"
+ " as long as you ignore the occasional odd look from the cityfolk staring at someone dressed in farmer's clothes.");
else if (characterRace == "elf")
System.out.print("While an elf isn't the most common sight around town, the locals seem like they don't care one way or another "
+ "about you wandering the streets. ");
}
}
答案 0 :(得分：1)
你比较给了while (raceBoolean=false)（赋值运算符）。其次是使用==运算符比较字符串。但是在java字符串中使用.equals()方法进行比较。我修改了你的代码。
这是完整的工作代码
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
// TODO Auto-generated method stub
//insert input tool
Scanner input = new Scanner(System.in);
//create inventory object for gold and items
int gold = 10;
//create health points object
//address player with greeting
System.out.println("Welcome to your adventure!");
//ask for character name, race, and gender
System.out.println("What will your adventurer's name be?");
String Name = input.nextLine();
//create test to verify validity of race selection
boolean raceBoolean=true;
String characterRace = "";
try {
do {
//selection list that defines options
System.out.println("What will your adventurer's race be?");
System.out.println("1. Human");
System.out.println("2. Elf");
System.out.println("3. Orc");
System.out.println("4. Undead");
int raceInt = input.nextInt();
if (raceInt < 0 || raceInt > 4) {
raceBoolean = false;
}
else{
raceBoolean = true;
}
if (raceInt == 1){
characterRace = "human";
}
else if (raceInt == 2)
characterRace = "elf";
else if (raceInt == 3)
characterRace = "orc";
else if (raceInt == 4)
characterRace = "undead";
System.out.println(raceInt);
}
while (raceBoolean==false);
}
finally {
}
//ask for character gender
System.out.println("What will your adventurer's gender be?");
System.out.println("1. Male");
System.out.println("2. Female");
int genderInt = input.nextInt();
String characterGender = "";
if (genderInt == 1)
characterGender = "male";
else if (genderInt == 2)
characterGender = "female";
System.out.println(characterRace);
//list out character description
System.out.println("You are " + Name + ", a " + characterGender + " " + characterRace + ".");
//introduce player to adventure with different introductions for different races
System.out.print("You came to Glassolin with only ten gold pieces to your name. ");
if (characterRace.equals("human"))
System.out.print("Glassolin is home to many humans; some from the far reaches of the realm. You feel right at home, more or less,"
+ " as long as you ignore the occasional odd look from the cityfolk staring at someone dressed in farmer's clothes.");
else if (characterRace.equals("elf"))
System.out.print("While an elf isn't the most common sight around town, the locals seem like they don't care one way or another "
+ "about you wandering the streets. ");
}
}
答案 1 :(得分：0)
这里易于解决的问题， 你刚才在if语句中出现了逻辑错误
if (raceInt < 0 || raceInt > 4) {
检查raceInt是小于0还是大于4
但我们希望看看是否符合（0,4）的范围（您的分类是1,2,3和4） 所以我们想要的是： if（raceInt＆gt; 0＆amp;＆amp; raceInt＆lt; = 4）
switch case语句将是一种更好的可读方式
while (characterRace.isEmpty()) {
switch (raceInt) {
case 1:
characterRace = "human";
break;
case 2:
characterRace = "elf";
break;
case 3:
characterRace = "orc";
break;
case 4:
characterRace = "undead";
break;
default:
System.out.println("Nice try. Enter a valid number for one of the four races!");
break;
}
}
顺便说一句： 属性/变量的名称约定是非大写的（因此只需将变量Name更改为name）
您也可能想要注意有更好的方法来做这些事情 https://docs.oracle.com/javase/tutorial/java/javaOO/enum.html
答案 2 :(得分：0)
从以下开始：
System.out.println("4. Undead");
此代码应继续询问有效答案，直到给出答案。
//create test to verify validity of race selection
String characterRace = "";
boolean raceBoolean = false;
Do{
int raceInt = input.nextInt();
if (raceInt == 1){
characterRace = "human";
raceBoolean = true;
}else{
if (raceInt == 2){
characterRace = "elf";
raceBoolean = true;
}else{
if (raceInt == 3){
characterRace = "orc";
raceBoolean = true;
}else{
if (raceInt == 4){
characterRace = "undead";
raceBoolean = true;
}else{
raceBoolean = false;
System.out.println("Nice try. Enter a valid number for one of the four races!");
}
}
}
}
}while(raceBoolean = false)
它将输入放在do while语句中，以便它可以重复请求不同的输入。此外，我将布尔值初始化为false，就像故障安全一样。最后的while语句测试是否给出了有效的输入。
使用嵌套的if / else语句进行测试。