Question

我想检查数组并找到包含某个东西的数组

我有一个包含这些值的cartarray

  {id: "1510-01-312-3501-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514542566148", name: "AIRPLANE UTILITY", price: "$90", quantity: "1"}

  {id: "1510-01-312-3501-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514542566148", name: "AIRPLANE UTILITY", price: "$90", quantity: "1"}

  {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "3"}

  {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "1"}

  {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "1"}

每个对象代表一个产品我真正想做的是防止重复id，所以如果id是相同的，我想巩固数量。所以在我添加这种格式的新产品对象之前

{id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "7"}

我想检查一下cartarray中是否有类似的产品

var arrayLength = cartarry.length;
for (var i = 0; i < arrayLength; i++) { 
    if (cartarry[i] == product.id ){
        console.log("we got a match")           
        var updatedquantity = quantity + parseInt(product.quantity) 
    }
}

我尝试了几种不同的方法但不成功。如何找到匹配的ID并更新数量？我希望我的描述清楚

Answer 1

我会解决这个问题。这条线

getUser

应该是

if (cartarray[i] == product.id) {

此外，如果只有零个或一个与product.id匹配的cartarray条目，请考虑在累加器之后暂停。

Answer 2

要按ID使用Array.prototype.reduce合并产品数量：

let data = [
  {id: "1510-01-312-3501-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514542566148", name: "AIRPLANE UTILITY", price: "$90", quantity: "1"},
  {id: "1510-01-312-3501-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514542566148", name: "AIRPLANE UTILITY", price: "$90", quantity: "1"},
  {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "3"},
  {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "1"},
  {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "1"}
];

data = data.reduce((acc, item) => {
  const foundItem = acc.find(_item => _item.id === item.id);
  if(foundItem) {
    foundItem.quantity = Number(item.quantity) + Number(foundItem.quantity) + '';
  }
  else {
    acc.push(item);
  }
  return acc;
}, []);

console.log(data);

//0: {id: "1510-01-312-3501-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514542566148", name: "AIRPLANE UTILITY", price: "$90", quantity: "2"}
//1: {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "5"}

<强> UPD 即可。借助reduce方法，我们希望获得原始数据数组的处理副本。输出数组形成为acc累加器值，最初是一个空数组（由reduce的最后一个参数调节：[]）。初始数据集的每个项目在回调中被单独考虑为item局部变量，我们正在根据当前acc内容更改item。我们正在尝试通过item查找当前acc数组中的当前id以合并数量。否则，如果当前item数组的当前acc是唯一的，我们会将当前item推送到acc。

Answer 3

t:([] td:2001.01.01 2001.01.02 2001.01.03 2001.01.04 2001.01.05 2001.01.06; 
AA:121.5 125.0 127.0 126.0 129.2 130.0; 
BB:111.0 115.3 117.0 116.0 119.2 120.0; 
wAA: 0.2 0.2 0.3 0.4 0.5 0.9; 
wBB: 0.8 0.8 0.7 0.6 0.5 0.1; 
fv:100000 0N 0n 0n 0n 0n;
sAA: 0n;
sBB: 0n)
t

kt:`td xkey t
// Calculate the first row of shares owned
kt:update sAA:fv*wAA%AA, sBB:fv*wBB%BB from kt
kt

// Global variables for previous shares owned
gPrevSAA:1.0
gPrevSBB:1.0

// Function to calclate the FV. If any of the previous shares owned paraeters are
// null then use the global parameters.
calcFV:{[fv;pSAA;pxA;pSBB;pxB]
    // The first time calcFV is called, pSAA will be defined. The remainder it will be null.
    $[pSAA=0n;pSAA:gPrevSAA;pSAA:pSAA];
    $[pSBB=0n;pSBB:gPrevSBB;pSBB:pSBB];

    // Calculate the fund value
    uFV:-1;
    $[fv=0n;uFV:(pSAA*pxA)+(pSBB*pxB);uFV:fv];

    // update global values
    $[pSAA<>0n;`gPrevSAA set pSAA;];
    $[pSBB<>0n;`gPrevSBB set pSBB;];
    uFV
}

// Calculate the fund values
kt:update fv:calcFV ' [fv;prev sAA;AA;prev sBB;BB] from kt

// Update the shares owned columns with the newly calcualted fund values
kt:update sAA:fv*wAA%AA, sBB:fv*wBB%BB from kt

您的帖子中没有大量信息，所以我猜了几件事。关键细节是：

您无法将var arrayLength = cartarry.length; var match = false; for (var i = 0; i < arrayLength; i++) { if (cartarry[i].id == product.id ) { console.log("we got a match") cartarry[i].quantity += parseInt(product.quantity); match = true; break; // because this can only happen once per array } } if (!match) { // add it to the array }与product.id进行比较。 cartarry[i]包含一个包含字段cartarry[i]，id，name和price的对象。您必须使用这些字段进行比较，以及更新。

Answer 4

尝试这种方法：

 var grouped = [];
 var array = [{id: "1510-01-312-3501-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514542566148", name: "AIRPLANE UTILITY", price: "$90", quantity: "1"},
      {id: "1510-01-312-3501-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514542566148", name: "AIRPLANE UTILITY", price: "$90", quantity: "1"},
      {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "3"},
      {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "1"},
      {id: "1510-00-033-6312-OkqcPp3xJwfgmNinwGsKZmAa8xt1-1514540733034", name: "AIRPLANE UTILITY", price: "$43", quantity: "1"}]

array.forEach(function (o) {
    if (!this[o.id]) {
        this[o.id] = { id: o.id, name:o.name, price:o.price, quantity: 0 };
        grouped.push(this[o.id]);
    }
    this[o.id].quantity += parseInt(o.quantity);
}, Object.create(null));

console.log(grouped);

如何更新数组对象的数组特定属性

4 个答案: