Question

我的网站标题中有一个按钮，它必须在第一次点击时打开/更改另一个div显示状态。但它在第一次点击时没有响应，我无法找到错误。我很感激帮助..

＆＃13;

open System
open System.IO
open System.Linq
open System.Security.AccessControl
open System.Security.Principal

let checkSecurity  =
    let account = sprintf @"%s\%s" Environment.UserDomainName Environment.UserName
    let identity = WindowsIdentity.GetCurrent()
    let principal = identity |> WindowsPrincipal
    let isAdmin = identity.Owner = identity.User
    fun (dir: DirectoryInfo) ->
        try
            let acl = dir.GetAccessControl(AccessControlSections.All)
            let rules = acl.GetAccessRules(true, true, typeof<NTAccount>)
            rules.OfType<FileSystemAccessRule>() 
            |> Seq.filter (fun rule -> rule.IdentityReference.Value.Equals(account, StringComparison.CurrentCultureIgnoreCase) || 
                           (if rule.IdentityReference.Value.Equals("BUILTIN\Administrators", StringComparison.CurrentCultureIgnoreCase) 
                            then isAdmin && principal.IsInRole(rule.IdentityReference.Value)
                            else principal.IsInRole(rule.IdentityReference.Value)))
            |> Seq.exists (fun rule -> (rule.FileSystemRights &&& FileSystemRights.Read = FileSystemRights.Read) && rule.AccessControlType <> AccessControlType.Deny)
        with | _ -> 
            false

let rec getFiles (dir: DirectoryInfo) =
    [ if checkSecurity dir
      then for file in dir.GetFiles("*") do yield file
           for subDir in dir.GetDirectories("*") do yield! getFiles subDir
    ]

let dir = DirectoryInfo(@"C:\Temp")
dir |> getFiles

＆＃13;

/* show search div */
function ShowSearchDiv() {
  var searchbox = document.getElementById("header-search-form");
  if (searchbox.style.display === "none") {
    searchbox.style.display = "block";
    document.getElementById("search-icon").classList.remove('fa-search', 'fa-lg2');
    document.getElementById("search-icon").classList.add('fa-close', 'fa-lg-sm');

  } else {
    searchbox.style.display = "none";
    document.getElementById("search-icon").classList.remove('fa-close', 'fa-lg-sm');
    document.getElementById("search-icon").classList.add('fa-search', 'fa-lg2');
  }
}

＆＃13;

Answer 1

我发现了错误并将if语句更改为：

＆＃13;

<script>
/* show search div */
function ShowSearchDiv() {
    var searchbox = document.getElementById("header-search-form");
    if (searchbox.style.display === "block") {
        searchbox.style.display = "none";
          document.getElementById("search-icon").classList.remove('fa-close', 'fa-lg-sm');
          document.getElementById("search-icon").classList.add('fa-search', 'fa-lg2');  

      }
      else {
        searchbox.style.display = "block"; 
            document.getElementById("search-icon").classList.remove('fa-search', 'fa-lg2');
            document.getElementById("search-icon").classList.add('fa-close', 'fa-lg-sm');
         } 
}

</script>

＆＃13;

这种方式不是检查＆＃34;如果div被隐藏，那么让它可见，然后隐藏它......＆＃34;，我把它改为＆＃34;如果div是可见的，那么make它隐藏了，否则让它可见:) 现在它正在进行第一次点击。

按钮在第一次点击时没有响应

1 个答案: