Question

我试图创建一个能够构造的类，并返回一个在某些时间点可调用的对象并向RabbitMQ发送消息

我正在使用Pika而我已经尝试过这段代码，但除非我打电话给ioloop但我不需要一个而且ioloop卡住我剩下的代码，但它不会启动叫这个班。

任何想法如何实现？

import pika

导入ConfigurationManager 导入json import gc

类MessageSender：

def __init__(self,brokerUrl,queueName):
    credentials = pika.PlainCredentials('admin', 'admin')        
    self.brokerUrl = brokerUrl
    self.queueName = queueName        
    self.channel = None
    self.connectionParameters = pika.ConnectionParameters(host=self.brokerUrl, credentials=credentials)
    self.connection = pika.SelectConnection(self.connectionParameters, on_open_callback=self.onOpen, custom_ioloop=None)                        

def onOpen(self, connection):
    connection.channel(self.openChannel)

def openChannel(self, channel):
    channel.queue_declare(None, queue=self.queueName, durable=True) 
    self.channel = channel

def createMessageJson(self,commandType,searchId,senderChannel,data,runId=None, originalMessage=None):
    rtnDict = {}
    rtnDict["commandType"] = commandType
    rtnDict["searchId"] = searchId
    rtnDict["receipientChannel"]  = self.queueName
    rtnDict["senderChannel"] = senderChannel
    rtnDict["data"] = data
    if 'executionPlanSchema' in data:
        rtnDict['executionPlanSchema'] = data['executionPlanSchema']
    if runId != None:
        rtnDict["runId"] = runId
    if originalMessage != None:
        rtnDict["originalMessage"] = originalMessage
    return rtnDict

#def sendMessage(self,msg):
#    tornado.ioloop.IOLoop.current().run_sync(lambda: self.send(msg))

def sendMessageAsync(self,msg):
    msg = json.dumps(msg)
    self.channel.basic_publish(exchange='', routing_key=self.queueName, body=msg)    
    gc.collect()

def sendMessage(self,msg):
    msg = json.dumps(msg)
    self.channel.basic_publish(exchange='', routing_key=self.queueName, body=msg)
    gc.collect()

Answer 1

RabbitMQ团队监控this mailing list，有时只回答StackOverflow上的问题。

请尝试使用BlockingConnection。

皮卡＆amp; RabbitMQ - 异步类处理程序

1 个答案: