两个陈述需要结合起来。
select INVOICEAMOUNT, itemid
from MTS_NONPAYMENT
select SUM(AMOUNT) AS SUM, ITEMID
from CUS_GLACCOUNT
公共专栏itemid
。每次我尝试加入时,都会失败。我做错了什么?
答案 0 :(得分:2)
从根本上说,您似乎缺少group by
。我怀疑以下是你想要的:
select itemid, sum(invoiceamount) as invoiceamount, sum(sum) as sum
from ((select itemid, sum(INVOICEAMOUNT) as invoiceamount, 0 as sum
from MTS_NONPAYMENT
group by itemid
) union all
(select itemid, 0, SUM(AMOUNT)
from CUS_GLACCOUNT
group by itemid
)
) x
group by itemid;
要获得不相等的值,请使用:
having sum(invoiceamount) <> sum(sum)
在查询结束时。