数字修正

Question

我正在用令我困惑的部分编写代码。

while answer1 != 'a':
    if answer1 == 'b':
        print('\nWrong answer.\n')
    answer1= input("\nEnter again.\nYou only have one more try!\n")
    amount = amount+1
    print(amount)#for testing
    if amount == 1:
        print("\nTry next question")
    break

如果用户说“b＆＃39;两次。我已将金额设为1，但如果用户说a，那么它将是2。我想要做的是尝试两个如果＆＃39; b＆＃39;有两次，但有一次，如果＆＃39; a＆＃39;曾经说过一次。

Answer 1

所以，这里的总体目标尚不清楚。但是，我认为这可能会帮助你：

首先，放弃while answer != 'a'，然后转到while True，依靠循环内的条件来处理break / continue。

amount = 1 # Initiate amount outside of the loop, otherwise it'll get reset on each loop.
while True: # Run until base condition is met.
    print("I am the question")
    ANSWER = input("Answer: ")
    if ANSWER == 'a' or amount >= 2: # Base condition.
        print(amount)
        break 
    else: # This runs if answer isn't what you want.
        print("Wrong, please try again.")
        amount += 1
        continue

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