我正在尝试了解SynchronizedMap并运行以下代码。我得到以下输出异常。根据我的理解,当线程仍然在地图上执行写入或者线程处于休眠状态时,get()方法试图访问同步映射时会导致异常。我的理解是正确还是我错过了什么?
class MapHelper1 implements Runnable {
Map<String, Integer> map;
public MapHelper1(Map<String, Integer> map) {
this.map = map;
new Thread(this, "MapHelper1").start();
}
public void run() {
map.put("One", 1);
try {
System.out.println("MapHelper1 sleeping");
Thread.sleep(100);
} catch (Exception e) {
System.out.println(e);
}
}
}
class MapHelper2 implements Runnable {
Map<String, Integer> map;
public MapHelper2(Map<String, Integer> map) {
this.map = map;
new Thread(this, "MapHelper3").start();
}
public void run() {
map.put("two", 1);
try {
System.out.println("MapHelper2 sleeping");
Thread.sleep(100);
} catch (Exception e) {
System.out.println(e);
}
}
}
class MapHelper3 implements Runnable {
Map<String, Integer> map;
public MapHelper3(Map<String, Integer> map) {
this.map = map;
new Thread(this, "MapHelper3").start();
}
public void run() {
map.put("three", 1);
try {
System.out.println("MapHelper3 sleeping");
Thread.sleep(100);
} catch (Exception e) {
System.out.println(e);
}
}
}
public class MainClass {
public static void main(String[] args) {
Map<String, Integer> hashMap = new HashMap<>();
Map<String, Integer> syncMap = Collections.synchronizedMap(hashMap);
MapHelper1 mapHelper1 = new MapHelper1(syncMap);
MapHelper2 mapHelper2 = new MapHelper2(syncMap);
MapHelper3 mapHelper3 = new MapHelper3(syncMap);
for (Map.Entry<String, Integer> e : syncMap.entrySet()) {
System.out.println(e.getKey() + "=" + e.getValue());
}
}
}
输出:
MapHelper1 sleeping
MapHelper2 sleeping
MapHelper3 sleeping
Exception in thread "main" java.util.ConcurrentModificationException
at java.base/java.util.HashMap$HashIterator.nextNode(HashMap.java:1494)
at java.base/java.util.HashMap$EntryIterator.next(HashMap.java:1527)
at java.base/java.util.HashMap$EntryIterator.next(HashMap.java:1525)
at MainClass.main(MainClass.java:137)
Command exited with non-zero status 1
编辑:当生成输出时,我再次运行代码几次。为什么会出现这种情况?
答案 0 :(得分:3)
迭代时不要同步访问权限。使用:
@Component
public class CustomAuthenticationFailureHandler extends SimpleUrlAuthenticationFailureHandler {
@Override
public void onAuthenticationFailure(HttpServletRequest request, HttpServletResponse response,
AuthenticationException exception) throws IOException, ServletException {
this.logger.debug("No failure URL set, sending 401 Unauthorized error");
response.sendError(403, "Authentication Failed: " + exception.getMessage());
}
}
甚至在synchronizedMap()
方法javadoc
用户必须手动同步返回的内容 迭代任何集合视图时映射:
synchronized(syncMap) {
for (Map.Entry<String, Integer> e : syncMap.entrySet()) {
System.out.println(e.getKey() + "=" + e.getValue());
}
}
答案 1 :(得分:2)
我刚看完@Dariusz的回答,我认为这是完全正确的。
要具体回答为何看到随机行为,这完全是时机。也就是说,如果在主线程中迭代之前地图已被所有三个线程填充,那么一切都很好。但是如果一个线程尝试填充,而主线程中的迭代已经在进行中,那么就会得到异常。
是的,我知道这是出于演示目的。但在实际代码中,最好不要在构造函数中启动线程。