Question

下面的代码获取了我的右侧行，但是我只想返回一个值，而不必在其上放置更多（任何）CASE。我可以重新检查该行中的两个值中的哪一个是最低的，但是我所寻找的实际值在现实世界中并不是按字母顺序排列的。＆＃39;从而为它们分配价值。

如果我找回最低的字段文本或CASE编号，即理想的20。我不知道下一步该去哪里，没有重新检查这两个字段。

代码：

DECLARE @ID INT  = '1234';

WITH GetMyInfo AS 
(
SELECT field1, field2 , ID
              , ROW_NUMBER() OVER (PARTITION BY ID,NAME ORDER BY CASE
              WHEN ISNULL(field1, field2) = 'z' THEN 20
              WHEN ISNULL(field1, field2) = 'b' THEN 10
              WHEN ISNULL(field1, field2) = 't' or  ISNULL(field1, field2) = 'f' THEN 0   
ELSE 20
END) [RowNumber]
FROM TABLE
WHERE 
             (field1 IS NOT NULL OR field2 IS NOT NULL)
              AND ID= @ID 
)
SELECT    field, field2
FROM GetMyInfo 
WHERE RowNumber = 1

我喜欢Return RowNumberValue

之类的东西

Answer 1

嗯。嗯。。。我想你可以做到：

WITH GetMyInfo AS (
      SELECT t.*, field,
             ROW_NUMBER() OVER (PARTITION BY ID, NAME
                                ORDER BY (CASE WHEN field = 'z' THEN 20
                                               WHEN field = 'b' THEN 10
                                               WHEN field in ('t', 'b') THEN 0 
                                               WHEN field is null THEN 100
                                               ELSE 20
                                           END)) [RowNumber]
       FROM TABLE t CROSS APPLY
            (VALUES (field1), (field2)) as v(field)
       WHERE (field1 IS NOT NULL OR field2 IS NOT NULL) AND ID= @ID 
      )
SELECT  field
FROM GetMyInfo 
WHERE RowNumber = 1;

这会使数据无法显示，因此您只能返回匹配值。

Answer 2

你可以使用一个额外的查询来实现你想要的东西

DECLARE @ID INT  = '1234';

WITH GetMyInfo AS 
(
SELECT field1,field2,caseNumber,ROW_NUMBER() OVER (PARTITION BY ID,NAME 
ORDER BY [caseNumber] )[RowNumber]
FROM
(SELECT field1, field2 , ID,NAME
          ,  CASE
          WHEN ISNULL(field1, field2) = 'z' THEN 20
          WHEN ISNULL(field1, field2) = 'b' THEN 10
          WHEN ISNULL(field1, field2) = 't' or  ISNULL(field1, field2) = 'f' 
THEN 0   
ELSE 20
END) [caseNumber]
FROM TABLE
)A
WHERE 
             (field1 IS NOT NULL OR field2 IS NOT NULL)
              AND ID= @ID 
)
SELECT    field, field2,caseNumber
FROM GetMyInfo 
WHERE RowNumber = 1

根据行号或CASE选择提取值

2 个答案: