Question

我正在使用sails.socket发送消息。我的要求是，我必须在发送消息成功后发送推送通知。怎么可能。请参阅我编写的代码。

sendChatMessage(chatMessage, function() {
    // calling push notification when a chat message send
    var serverKey       =   req.options.settingsKeyValue.PUSH_SERVER_KEY;
    var typeData        =   { type:1, data:{type:1} };
    var pushData        =   { title:'New Message', body: data };
    pusherService.pushFcm(serverKey,typeData,pushData,toId, function(err, result) {
        if(err) {
            return res.json(200, {status:1, status_type: 'Success', message: 'Error in  sending the message'});
        }else{
            return res.json(200, {status:1, status_type: 'Success', message: 'You have successfully send the message'});
        }
    });
});

function sendChatMessage(){    
    var socketRoom      =   "userRoom_"+toId;
    var roomsSubcribers =   sails.sockets.subscribers(socketRoom);
    console.log("roomsSubcribers");
    console.log(roomsSubcribers);
    var data            =   {
        text: message,
        from_id: fromId,
        from_name: userResult[0].firstName+' '+userResult[0].lastName, from_img : userResult[0].profilePhoto,
    };
    sails.sockets.broadcast(socketRoom,{
        type : "chat",
        message : data,

    });
    callback(chatMessage);
}

Answer 1

这些代码块对我来说没问题......你只需将它们放在应用程序中的正确位置即可。你试过这个吗？

您肯定需要在sendChatMessage函数定义和回调函数中命名一些参数。

也许你需要这样的东西：

// in some controller

// notice the named arguments 'options' and 'callback'
var sendChatMessage = function(options, callback){    
    var socketRoom      =   "userRoom_"+options.toId;
    var roomsSubcribers =   sails.sockets.subscribers(socketRoom);
    console.log("roomsSubcribers");
    console.log(roomsSubcribers);
    var data            =   {
        text: options.message,
        from_id: options.fromId,
        from_name: options.fromName, 
        from_img : options.fromImg,
    };
    sails.sockets.broadcast(socketRoom,{
        type : "chat",
        message : data,
    });
    callback(data);
};

module.exports = {

    someMethod: function(req, res) {
        // do some work, including defining / getting all options
        var options = {
            toId: 123,
            fromId: 456,
            message: 'test message',
            fromName: 'test user',
            fromImg: 'some/image.jpg' // don't know if you need a source here or what
        };

        // invoke your function - notice the named argument in the callback
        sendChatMessage(options, function(data) {
            // calling push notification when a chat message send
            var serverKey       =   req.options.settingsKeyValue.PUSH_SERVER_KEY;
            var typeData        =   { type:1, data:{type:1} };
            var pushData        =   { title:'New Message', body: data };
            pusherService.pushFcm(serverKey,typeData,pushData,toId, function(err, result) {
                if(err) {
                    return res.json(200, {status:1, status_type: 'Success', message: 'Error in  sending the message'});
                }else{
                    return res.json(200, {status:1, status_type: 'Success', message: 'You have successfully send the message'});
                }
            });
        });
    },

};

我无法知道这是否是使用所有插件等的正确方法，但将这些部分放在一起似乎是有道理的。

最后请注意，当您定义自己的回调时，最好将第一个参数作为错误对象，并检查回调正文中收到的错误。成功后，您可以返回空错误，例如callback(null, data);。

希望这有用。

发送消息后执行推送通知

1 个答案: