在Doctrine中计算行数

Question

我想在SearchResult中计算独特的$ hotel。我在视图中传递新变量。

类别：

 * 
     *
     * @ORM\Entity(repositoryClass="Uts\HotelBundle\Repository\SearchResult")
     * @ORM\Table(name="search_result")
     */
    class SearchResult
    {
        ------
        /**
         * @ORM\ManyToOne(targetEntity="SearchRequest")
         * @var
         */
        private $request;

        /**
         * @ORM\ManyToOne(targetEntity="Hotel")
         * @var Hotel
         */
        private $hotel;
    ---
    }

将变量传递给视图：

   $query2 = $repository->hotelsCount($searchId);
             //  var_dump($query2);
               $templateVars['count']=$query2;
            }
            return $this->render('UtsHotelBundle:Default:results.html.twig', $templateVars)

功能酒店数量：

  public function hotelsCount($requestId){

     $qb = $this->createQueryBuilder('self');
    $qb->select('count DISTINCT(p.hotel)');
    $qb->from('HotelBundle:SearchResult','p')
        ->where('p.request_id = :id')
        ->setParameter('id',$requestId);
    $count = $qb->getQuery()->getSingleScalarResult();
    }

表searchResult：

Answer 1

我会做一个像

这样更可重复的查询

public function getHotelsByRequest($requestId){

    $qb = $this->createQueryBuilder('self');
    $qb
        ->where('self.request_id = :id')
        ->setParameter('id',$requestId);
    return $qb->getQuery()->getResult();
}

然后在您的控制器中

$hotels = $repository->getHotelsByRequest($searchId);
$templateVars['count']= count($hotels);