TOML文档上的可链接查询

时间:2018-01-17 17:34:22

标签: generics recursion rust traits toml

我正在尝试为TOML文档实现可链接的查询执行。

Query是更改TOML文档并可能返回另一个Query对象的对象,该对象将在其自身之后执行。执行的Query获取上一个查询的结果(如果有)。

问题是返回类型是通用的。查询可能返回Vec<i64>,但其后继可能会返回String ...因此,返回类型为Query直接取决于其后继的返回类型。

到目前为止,这是我的代码:

extern crate either;
extern crate toml;

use either::Either;
use toml::Value;

type Result<T> = ::std::result::Result<T, ()>; // for simplicity

pub trait Query<Prev>
where
    Prev: Sized,
    Self: Sized,
{
    type Output: Sized;
    type Next: Query<Self::Output>;

    fn execute(&self, target: &mut Value, prev_result: Option<Prev>) -> Result<Self::Output>;

    fn next(self) -> Option<Self::Next>;
}

fn execute_query<Q, Prev>(
    doc: &mut Value,
    query: &Q,
    prev_result: Option<Prev>,
) -> Result<Either<Q::Output, <Q::Next as Query<Q::Output>>::Output>>
where
    Q: Query<Prev>,
{
    let result = query.execute(doc, prev_result)?;

    if let Some(next_query) = query.next() {
        let next_result: <Q::Next as Query<Q::Output>>::Output =
            match execute_query(doc, &next_query, Some(result)) {
                Ok(Either::Left(t)) => t,
                Ok(Either::Right(t)) => return Ok(Either::Right(t)), // error happens here
                Err(e) => return Err(e),
            };

        Ok(Either::Right(next_result))
    } else {
        Ok(Either::Left(result))
    }
}

playground

错误是返回类型是递归的(因为整个问题是递归的):

error[E0308]: mismatched types
  --> src/main.rs:37:65
   |
37 |                 Ok(Either::Right(t)) => return Ok(Either::Right(t)), // error happens here
   |                                                                 ^ expected type parameter, found associated type
   |
   = note: expected type `<<Q as Query<Prev>>::Next as Query<<Q as Query<Prev>>::Output>>::Output`
              found type `<<<Q as Query<Prev>>::Next as Query<<Q as Query<Prev>>::Output>>::Next as Query<<<Q as Query<Prev>>::Next as Query<<Q as Query<Prev>>::Output>>::Output>>::Output`

标题不是很有表现力。对不起,我不知道如何更好地描述。

1 个答案:

答案 0 :(得分:2)

问题的整个方法是错误的。我通过以下方式实现它:

  • Query特征提供链接查询的功能。该函数返回Chain
  • Chain类型通过执行第一个元素并将结果(如果Query)传递给第二个查询来实现Ok

使用此问题可以解决:

use std::marker::PhantomData;

use toml::Value;
use error::Result;

pub trait Query<Prev>
where
    Prev: Sized,
    Self: Sized,
{
    type Output: Sized;

    fn execute(&self, target: &mut Value, prev_result: Option<Prev>) -> Result<Self::Output>;

    fn chain<Q>(self, other: Q) -> Chain<Self, Prev, Q>
    where
        Q: Query<Self::Output>,
    {
        Chain {
            first: self,
            _p: PhantomData,
            second: other,
        }
    }
}

pub struct Chain<A, P, B>
where
    A: Query<P>,
    B: Query<A::Output>,
    P: Sized,
{
    first: A,
    _p: PhantomData<P>,
    second: B,
}

impl<A, P, B> Query<P> for Chain<A, P, B>
where
    A: Query<P>,
    B: Query<A::Output>,
    P: Sized,
{
    type Output = B::Output;

    fn execute(&self, target: &mut Value, prev_result: Option<P>) -> Result<Self::Output> {
        let p = self.first.execute(target, prev_result)?;
        self.second.execute(target, Some(p))
    }
}

pub trait QueryExecutor {
    fn query<Q, T>(&mut self, q: &Q) -> Result<Q::Output>
    where
        Q: Query<T>;
}

impl QueryExecutor for Value {
    fn query<Q, T>(&mut self, q: &Q) -> Result<Q::Output>
    where
        Q: Query<T>,
    {
        q.execute(self, None as Option<T>)
    }
}

(完整代码包括测试here