Question

这应该很简单。

＆＃34;语法错误在或附近＆＃34;当＆＃34;＆＃34;第5行错误

    round(CAST(CASE WHEN x.sprd_units = 0 then 0 ELSE 
        case 
        when sum(case when d.ver_desc_txt = 'BEST OFFICIAL PROJECTION' AND d.veh_desc_txt in ('CORE BROCHURE','CORE BROCHURE ATTACHED','CORE BROCHURE UNATTACHED') 
            THEN d.unit_qty else 0 end) / z.spread_units_cb::numeric
        when sum(case when d.ver_desc_txt = 'BEST OFFICIAL PROJECTION' AND d.veh_desc_txt not in ('CORE BROCHURE','CORE BROCHURE ATTACHED','CORE BROCHURE UNATTACHED') 
            THEN d.unit_qty else 0 end) / x.sprd_units::numeric
        end as numeric) 2) as space_units,

Postgresql版本是8.3

我错过了什么或什么？提前致谢

Answer 1

你在这里发生了大量的嵌套，还有一些括号用于启动。我处理像这样的混乱的方式就是像一个疯狂的人一样缩进它。你很快就会发现你错过了一些与某些WHEN条款匹配的THEN条款，而那些相同的WHEN条款缺少条件。你只是在划分某些东西（而不是比较某些东西）。最后，您错过了一个CASE语句的END。

round(
    CAST(
        CASE 
            WHEN x.sprd_units = 0 
                then 0 
            ELSE 
                case 
                    when sum(
                                case 
                                    when d.ver_desc_txt = 'BEST OFFICIAL PROJECTION' AND d.veh_desc_txt in ('CORE BROCHURE','CORE BROCHURE ATTACHED','CORE BROCHURE UNATTACHED') 
                                        THEN d.unit_qty 
                                    else 0 
                                    end
                            ) / z.spread_units_cb::numeric
                        /*WHEN this is what? there is no condition here, just math*/
                        /*WHERE IS THE THEN ?*/
                    when sum(
                                case 
                                    when d.ver_desc_txt = 'BEST OFFICIAL PROJECTION' AND d.veh_desc_txt not in ('CORE BROCHURE','CORE BROCHURE ATTACHED','CORE BROCHURE UNATTACHED') 
                                        THEN d.unit_qty 
                                    else 0 
                                    end
                            ) / x.sprd_units::numeric
                        /*WHEN this is what? there is no condition here, just math*/
                        /*AGAIN NO THEN*/
                    /*THIS CASE IS MISSING AN END*/
        end as numeric
    ), 2
) as space_units,

Answer 2

所有这些嵌套都是不需要的。 CASE支持多种条件。您缺少两个CASE条件（下面标有?），但我假设第二个是ELSE。您在＆＃34; 2＆＃34;：

之前也缺少逗号

round(cast(case when x.sprd_units = 0 then 0 
                when ?
                then sum(case when d.ver_desc_txt = 'BEST OFFICIAL PROJECTION' AND d.veh_desc_txt in ('CORE BROCHURE', 'CORE BROCHURE ATTACHED', 'CORE BROCHURE UNATTACHED') 
                              then d.unit_qty
                              else 0
                         end) / z.spread_units_cb::numeric
                else sum(case when d.ver_desc_txt = 'BEST OFFICIAL PROJECTION' AND d.veh_desc_txt not in ('CORE BROCHURE', 'CORE BROCHURE ATTACHED', 'CORE BROCHURE UNATTACHED') 
                              then d.unit_qty else 0
                         end) / x.sprd_units::numeric
           end as numeric), 2) as space_units,

Answer 3

我终于做到了：

round(CAST(sum(d.unit_qty / case 
                                    when d.veh_desc_txt in ('CORE BROCHURE','CORE BROCHURE ATTACHED','CORE BROCHURE UNATTACHED') and d.ver_desc_txt = 'BEST OFFICIAL PROJECTION'
                                        then nullif(z.spread_units_cb, 0)::numeric
                                    when d.veh_desc_txt not in ('CORE BROCHURE','CORE BROCHURE ATTACHED','CORE BROCHURE UNATTACHED') and d.ver_desc_txt = 'BEST OFFICIAL PROJECTION'
                                        then nullif(x.sprd_units, 0)::numeric

                                    end)
            as numeric),                        
        2) as space_units,

语法错误在或附近＆＃34;当＆＃34;

3 个答案: