Question

如何连接2个不包含外键列的表变量。

DECLARE @InventoryIDList TABLE(ID INT)
DECLARE @ProductSupplierIDList TABLE(ID INT)

例外输出

@InventoryList
--------------
123
456
789
111

@ProductSupplierIDList
--------------
999
888
777
666

@InventoryList    ProductSupplierIDList
---------------------------------------
123             |        999
567             |        888
789             |        777
111             |        666

所有都是随机数据。我只想将2表变量结合起来如上所示。我尝试了所有类型的连接。但我需要提到上面提到的输出而没有null值。

我尝试了CROSS APPLY

SELECT *
FROM @InventoryIDList invList CROSS APPLY @ProductSupplierIDList prdList

但它给了我5 ^ 2个元素作为重复的结果。

Answer 1

我猜您需要Row_Number和Full Outer Join，考虑到这两个表之间没有关系

SELECT I.ID,
       P.ID
FROM   (SELECT Rn = Row_number()OVER(ORDER BY ID),*
        FROM   @InventoryList) I
       FULL JOIN (SELECT Rn = Row_number()OVER(ORDER BY ID),*
                  FROM   @ProductSupplierIDList) p
              ON I.RN = P.RN

Answer 2

由于ID不按顺序排列且可以是随机的，我建议在表变量上使用Identity并加入：

import { Pipe, PipeTransform } from '@angular/core';
import { Observable } from "rxjs/Observable";
import "rxjs/add/operator/map";

@Pipe({
  name: 'map'
})
export class MapPipe implements PipeTransform {

  transform(o$, propsNames): any {
    return o$.map(res => {
      return propsNames.reduce((acc, cur) => {
        acc[cur] = res[cur];
        return acc;
      }, {})
    })
  }

}

Answer 3

假设JOIN条件是按递增ID顺序的相同“行号”：

WITH invList AS (
    SELECT *,
           ROW_NUMBER() OVER (ORDER BY ID) AS RN
    FROM @InventoryIDList),
prdList AS (
    SELECT *,
           ROW_NUMBER() OVER (ORDER BY ID) AS RN
    FROM @ProductSupplierIDList)
SELECT *
FROM invList IL
     JOIN prdList PL ON IL.RN = PL.RN;

在SQL中加入2个表变量

3 个答案: