Question

我正在尝试验证在WPF中的Datagrid中输入的输入。

我已经向XAML添加了验证规则。

输入是一个对象，只是一个字符串或int。虽然我使用的方法需要一个对象。

如何解决问题并使其与int或字符串一起使用。输入只能是1到20之间的int。

XAML ：

<DataGridTextColumn Header="Niveau">                                
    <DataGridTextColumn.Binding>                                                                 
        <Binding Path="Niveau" UpdateSourceTrigger="LostFocus">
            <Binding.ValidationRules>                                       
                <valRule:NiveautredeValidationRule  />                                             
            </Binding.ValidationRules>
        </Binding>                                          
    </DataGridTextColumn.Binding>                                               
</DataGridTextColumn>

C＃

public class NiveautredeValidationRule : ValidationRule
{
    public override System.Windows.Controls.ValidationResult Validate(object value, System.Globalization.CultureInfo cultureInfo)
    {
        NiveaudoelenViewModel doel = (value as BindingGroup).Items[0] as NiveaudoelenViewModel;
        if (doel.Niveau <= 0 || doel.Niveau > 20)
        {
            return new System.Windows.Controls.ValidationResult(false, "Niveau moet tussen de 1 en 20 zijn!");
        }
        else
        {
            return System.Windows.Controls.ValidationResult.ValidResult;
        }
    }
}

Answer 1

你可以试试这个：

public override System.Windows.Controls.ValidationResult Validate(object value, 
    System.Globalization.CultureInfo cultureInfo)
{
    int myInt = 0;

    try
    {
        if (((string)value).Length > 0)
            myInt = int.Parse((String)value);
    }
    catch (Exception e)
    {
        return new ValidationResult(false, "Illegal characters or " + e.Message);
    }

    if (myInt < 0 || myInt > 20)
    {
        return new ValidationResult(false,
          "Please enter a number in the range: 0 - 20");
    }
    else
    {
        return new ValidationResult(true, null);
    }
}

来源：https://docs.microsoft.com/en-us/dotnet/framework/wpf/data/how-to-implement-binding-validation

Answer 2

你应该考虑更新这个的受理答案，这消除了foreach (System.Windows.Forms.Control e in this.Controls) { ElementHost c= e as ElementHost; if ( c != null ) { TP1WPFControls.TP1CustomButton bt = c.Child as TP1CustomButton; if ( bt != null ) { // Add Events (I'd assume it would just be bt.MouseEnter but I don't know what your control looks like) bt.bt.MouseEnter += Bt_MouseEnter; bt.bt.MouseLeave += Bt_MouseLeave; } } }并使用TryParse代替

try catch

验证输入wpf datagrid

2 个答案: