如何从XS访问当前上下文?

时间:2018-01-17 11:17:36

标签: perl perl-xs perlapi

当用户从XS包中调用main::时,我们无法使用

caller_cx(0, NULL);

因为main::XSUB DOC没有框架

  

请注意,XSUB不会获得堆栈帧,因此C将返回紧邻的Perl代码的信息

如何获取调用file:line的{​​{1}}信息,提示XSUB范围等信息?

1 个答案:

答案 0 :(得分:4)

mess_sv复制(由Perl API函数warncroak调用,它附加了Perl函数warndie等行信息):< / p>

use strict;
use warnings;
use feature qw( say );

use Inline C => <<'__EOS__';

void testing() {
    dXSARGS;

    /*
     * Try and find the file and line for PL_op.  This will usually be
     * PL_curcop, but it might be a cop that has been optimised away.  We
     * can try to find such a cop by searching through the optree star ting
     * from the sibling of PL_curcop.
     */
    if (PL_curcop) {
        const COP *cop =
            Perl_closest_cop(aTHX_ PL_curcop, OpSIBLING(PL_curcop), PL_op, FALSE);
        if (!cop)
            cop = PL_curcop;

        if (CopLINE(cop)) {
            EXTEND(SP, 2);
            mPUSHs(newSVpv(OutCopFILE(cop), 0));
            mPUSHs(newSViv((IV)CopLINE(cop)));
            XSRETURN(2);
        }
    }

    XSRETURN(0);
}

__EOS__

say join ":", testing();

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