我有4个表产品，属性，property_items，property_product，关系像这样 产品有很多属性。 物业有很多property_items。 产品有很多property_items。 Property_product是中间表。
-- products --
Id name
1 Arrabiata
2 Bolognese
--properties --
Id name
1 Pasta type
2 Size
-- property_items --
Id name value property_id
1 Spinach spaghetti ..... 1
2 Linguine ..... 1
3 Spaghetti ..... 1
4 Small .... 2
5 Medium .... 2
6 Large ... 2
-- property_product --
product_id property_id property_item_id
1 1 1
1 1 2
1 2 4
1 2 6
2 1 2
2 1 3
2 2 5
我尝试使用Gii创建具有关系的模型。
class Products extends \yii\db\ActiveRecord
{
//code
....
public function getProperties()
{
return $this->hasMany(Properties::className(), ['id' => 'property_id'])
->viaTable('property_product', ['product_id' => 'id']);
}
}
class Properties extends \yii\db\ActiveRecord
{
//code
...
public function getPropertyItems()
{
return $this->hasMany(PropertyItems::className(), ['property_id' => 'id']);
}
}
我想查询具有多嵌套关系的数据。 如何在一个活动记录查询中创建具有以下格式的json响应？
[
{
"id": "1",
"name": "Arrabiata",
"properties": [
{
"id": "1",
"name": "Pasta type",
"property_items" : [
{
"id": "1",
"name": "Spinach spaghetti",
},
{
"id": "2",
"name": "Linguine",
},
]
},
{
"id": "2",
"name": "Size",
"property_items" : [
{
"id": "4",
"name": "Small",
},
{
"id": "6",
"name": "Large",
},
]
},
],
},
{
"id": "2",
"name": "Bolognese",
"properties": [
{
"id": "1",
"name": "Pasta type",
"property_items" : [
{
"id": "2",
"name": "Linguine",
},
{
"id": "3",
"name": "Spaghetti",
},
]
},
{
"id": "2",
"name": "Size",
"property_items" : [
{
"id": "5",
"name": "Medium",
},
]
},
]
}]
我使用此查询但性能过高
Menus::find()->with(['products' => function ($query) {
$query->with(['properties']);
}])
->where(['>', 'status', 0])
->andWhere(['resid' => $id])->asArray()->all();;
foreach ($menus as &$menu) {
foreach ($menu['products'] as &$product) {
foreach ($product['properties'] as &$property) {
$propertyItems = PropertyItems::find()->where(['property_id' => $property['id']]
)
->leftJoin('property_product', 'property_items.id = property_product.property_item_id')
->where(['property_product.product_id' => $product['id'],
'property_product.property_id' => $property['id']])
->asArray()->all();
$property['propertyItems'] = $propertyItems;
}
}
}
如果我使用此查询
Menus::find()->with(['products' => function ($query) {
$query->with(['properties' => function ($query) {
$query->with(['propertyItems']);
}
]);
}
])->asArray()->all();
但结果与我预期的结果不一样，因为所有property_items都会显示在属性中，而不是依赖于通过表＆＃34; property_product＆＃34;
与产品相关联[
{
"id": "1",
"name": "Arrabiata",
"properties": [
{
"id": "1",
"name": "Pasta type",
"property_items" : [
{
"id": "1",
"name": "Spinach spaghetti",
},
{
"id": "2",
"name": "Linguine",
},
{
"id": "3",
"name": "Spaghetti",
},
]
},
{
"id": "2",
"name": "Size",
"property_items" : [
{
"id": "4",
"name": "Small",
},
{
"id": "6",
"name": "Large",
},
{
"id": "5",
"name": "Medium",
},
]
},
],
},
{
"id": "2",
"name": "Bolognese",
"properties": [
{
"id": "1",
"name": "Pasta type",
"property_items" : [
{
"id": "1",
"name": "Spinach spaghetti",
},
{
"id": "2",
"name": "Linguine",
},
{
"id": "3",
"name": "Spaghetti",
},
]
},
{
"id": "2",
"name": "Size",
"property_items" : [
{
"id": "4",
"name": "Small",
},
{
"id": "6",
"name": "Large",
},
{
"id": "5",
"name": "Medium",
},
]
}
]
}]
提前致谢。
答案 0 :(得分：0)
您必须覆盖fields()和Products模型的Properties功能。
例如：
class Products extends ActiveRecord {
function fields(){
return ['properties'];
}
}
class Properties extends ActiveRecord {
function fields(){
return ['property_items'];
}
}