获取类的XmlRoot

时间:2011-01-28 14:48:58

标签: c# .net xml-serialization

我想在XDocument中搜索SerializableClass内部的SerializableClass。如果typeof(SerializableClass).Name具有XmlRoot属性,则其名称将不同于{{1}}。如何查找此类的XmlRoot属性?

1 个答案:

答案 0 :(得分:2)

您的意思是您想要找到用于表示XML中某个元素的类的名称?

我就是这样做的:

/// <summary>
        /// Determines and returns the name of the XmlElement that should represent instances of the given type
        /// in an XML stream.
        /// </summary>
        /// <param name="serializedObjectType"></param>
        /// <returns></returns>        
        [SuppressMessage ("Microsoft.Design", "CA1011:ConsiderPassingBaseTypesAsParameters")]
        public static string GetRootNodeElementNameForType( Type serializedObjectType )
        {
            // Determine if the Type contains an XmlRoot Attribute.  If so, the XmlRoot attribute should contain
            // the name of the element-name for this type.
            // Otherwise, the name of the type should 've been used for serializing objects of this type.
            XmlRootAttribute theAttrib = Attribute.GetCustomAttribute (serializedObjectType, typeof (XmlRootAttribute)) as XmlRootAttribute;

            if( theAttrib != null )
            {
                if( String.IsNullOrEmpty (theAttrib.ElementName) == false )
                {
                    return theAttrib.ElementName;
                }
                else
                {
                    return serializedObjectType.Name;
                }
            }
            else
            {
                return serializedObjectType.Name;
            }
        }