我创建了一个表并从数据库中获取数据......但如果用户没有上传任何图像,那么我该如何在此表中上传默认图像。
提前谢谢。
下面是从数据库中提取数据的表。
这是数据库连接:
<?php
$con=mysqli_connect("localhost","krishna","krishna","krishna");
if (!$con) {
die("Connection failed: " . mysqli_connect_error());
}
?>
下面是从数据库中获取数据的表
<table id="contact-list" border='1' class="tblListForm">
<thead>
<tr class="listheader">
<th><input type="checkbox" name="select-all" id="select_all"></th>
<th> id </th>
<th> First name </th>
<th> Last name </th>
<th> User Name </th>
<th> Gender </th>
<th> Date Of Birth </th>
<th> Email-Id </th>
<th> Mobile Number </th>
<th> Image </th>
<th> Delete </th>
</tr>
</thead>
<?php
$result = mysqli_query($con,"SELECT * FROM employe");
while($row = mysqli_fetch_array($result))
{
// Change Date Format
$date = date('m-d-Y', strtotime(str_replace('/','-,$row['date_of_birth'])));
?>
<!-- fetching data from database -->
<tbody>`enter code here`
<tr>
<td><input type ='checkbox' value="<?=$row['select']?>"="<?=$row['select']?>" class="allcheckbox">
<td><?php echo $row['id'];?></td>
<td><?php echo $row['firstname'];?></td>
<td><?php echo $row['lastname'];?></td>
<td><?php echo $row['username'];?></td>
<td><?php echo $row['gender'] ;?></td>
<td><?php echo $date;?></td>
<td><?php echo $row['email'];?></td>
<td><?php echo $row['mobile_no'];?></td>
<td><img src="image/<?php echo $row['image'];?>" style="width:100px;height:100px;"></td> <!-- this is image that i fetched from my database -->
<td><form action='delete.php?name="<?php echo $row['id']; ?>" method="post"'><input type="hidden" name="id" value="<?php echo $row['id']; ?>"><input type="submit" name="submit" value="Delete"></form>
</td>
</tr>
</tbody>
<?php
}
?>
</table>