我正在尝试在Django上实现Paho MQTT,但Django在引发任何异常后停止接收/发送MQTT消息。
我正在使用Paho MQTT客户端1.3.0以及Django 1.10.8,Python 3.6.2
以下是我的MQTT设置:
mqtt.py
from django.conf import settings
import paho.mqtt.client as mqtt
SUB_TOPICS = ("device/vlt", "device/auth", "device/cfg", "device/hlt", "device/etracker", "device/pi")
RECONNECT_DELAY_SECS = 2
# The callback for when the client receives a CONNACK response from the server.
def on_connect(client, userdata, flags, rc):
print("Connected with result code " + str(rc))
# Subscribing in on_connect() means that if we lose the connection and
# reconnect then subscriptions will be renewed.
for topic in SUB_TOPICS:
client.subscribe(topic, qos=0)
# The callback for when a PUBLISH message is received from the server.
def on_message(client, userdata, msg):
print(msg.topic + " " + str(msg.qos) + " " + str(msg.payload))
def on_publish(mosq, obj, mid):
print("mid: " + str(mid))
def on_subscribe(mosq, obj, mid, granted_qos):
print("Subscribed: " + str(mid) + " " + str(granted_qos))
def on_log(mosq, obj, level, string):
print(string)
def on_disconnect(client, userdata, rc):
client.loop_stop(force=False)
if rc != 0:
print("Unexpected disconnection: rc:" + str(rc))
else:
print("Disconnected: rc:" + str(rc))
client = mqtt.Client()
client.on_connect = on_connect
client.on_message = on_message
client.on_publish = on_publish
client.on_subscribe = on_subscribe
client.on_disconnect = on_disconnect
client.username_pw_set(username, password)
client.connect(<settings>)
apps.py
class CoreConfig(AppConfig):
name = 'untitled.core'
verbose_name = "Core"
def ready(self):
from . import mqtt
mqtt.client.loop_start()
代码灵感:Paho MQTT client connection reliability (reconnect on disconnection)
答案 0 :(得分:1)
我的团队也遇到了这个问题,我们通过创建一个继承自CustomMqttClient
的{{1}}并覆盖mqtt.Client
函数来解决此问题。
_handle_on_message(self, message)
然后我们执行此操作而不是使用class CustomMqttClient(mqtt.Client):
def _handle_on_message(self, message):
try:
super(ChatqMqttClient, self)._handle_on_message(message)
except Exception as e:
error = {"exception": str(e.__class__.__name__), "message": str(e)}
self.publish("device/exception", json.dumps(error))
:
mqtt.Client()
这会捕获所有异常,并实际将其发布到我们的主题client = CustomMqttClient()
client.on_connect = on_connect
client.on_message = on_message
。我们的其他服务实际上可以订阅它,并从中获得一些有用的信息。