我正在尝试在上传到我的服务器之前旋转图像。我到目前为止采取的步骤是:
但我无法将其转换回图像格式。最终的图像文件(旋转后)无法上传,因为它是一个blob。
您能告诉我如何将我的旋转Base64字符串转换为图像文件,以便我可以创建一个blob并上传它。
我想我的旋转功能也不合适,因为我试图将其转换并将转换后的base64字符串视为https://codebeautify.org/base64-to-image-converter上的视图,它给了我一个空白文件(黑色图像文件)。
此问题的根源是当用户点击iOS或Android上的图片并上传图像时,图像会显示在侧面。为了解决这个问题,我试图根据EXIF方向旋转图像。
function detectFiles(event) {
this.getOrientation(event.target.files[0], function (orientation) {
this.imageOrientation = orientation;
}.bind(this));
console.log('the original image data', event.target.files);
this.selectedFiles = event.target.files;
// SAS : Converting the selected image to Base64 for rotation.
const reader = new FileReader();
reader.onloadend = (e) => {
this.base64Data = reader.result;
const rotatedData = this.rotateBase64Image(this.base64Data);
// SAS: Calling the data uri to blob
const selFile = this.dataURItoBlob(rotatedData);
this.uploadFiles(selFile);
}
reader.readAsDataURL(event.target.files[0]);
}
// SAS: Rotate the image.
function rotateBase64Image(base64ImageSrc) {
const canvas = document.createElement('canvas');
const img = new Image();
img.onload = function () {
canvas.width = img.width;
canvas.height = img.height;
console.log('image height and width', canvas.width , canvas.height);
}
img.src = base64ImageSrc;
const context = canvas.getContext('2d');
context.translate((img.width), (img.height));
// context.rotate(180 * (Math.PI / 180));
context.rotate(90);
context.drawImage(img, 0, 0);
console.log(canvas);
console.log('the rotated image', canvas.toDataURL());
return canvas.toDataURL();
}
// SAS: Data URI to Blob
function dataURItoBlob(dataURI) {
// convert base64 to raw binary data held in a string
// doesn't handle URLEncoded DataURIs
const byteString = atob(dataURI.split(',')[1]);
// separate out the mime component
const mimeString = dataURI.split(',')[0].split(':')[1].split(';')[0]
// write the bytes of the string to an ArrayBuffer
const ab = new ArrayBuffer(byteString.length);
// create a view into the buffer
const ia = new Uint8Array(ab);
// set the bytes of the buffer to the correct values
for (let i = 0; i < byteString.length; i++) {
ia[i] = byteString.charCodeAt(i);
}
// write the ArrayBuffer to a blob, and you're done
const blob = new Blob([ab], {type: mimeString});
console.log('the value of the blob', blob);
return blob;
}
在此之后,我尝试使用接受图像文件的以下功能上传数据。
uploadFiles(selFile) {
// SAS: Setting the 'image uploaded flag' to be retrieved in quick post to prevent duplicate placeholders.
// const file = this.selectedFiles.item(0);
const file = selFile;
this.currentUpload = new Upload(file);
// This is the API call to upload the file.
this.storageApiService.createBlob(file).subscribe((response) => {
console.log(response);
}, (error) => {
console.log(error);
});
}
}
答案 0 :(得分:0)
您可以为它们处理exif旋转,这样它们就不必旋转图像
我创建了一个库,永远不必使用名为screw-filereader的文件阅读器,只需调用blob.image().then(success, fail)
就可以非常轻松地从blob创建图像,并且它将处理图像exif旋转你。
// unrelevant code (just to get a rotated image with exif metadata)
var exifImage = 'https://cors-anywhere.herokuapp.com/http://duckz.serveblog.net/risorse/foto/francia/P1831_21-02-10.jpg'
fetch(exifImage)
.then(res => res.blob())
.then(blob => {
// just to show the problem you have with your image
const objectURL = URL.createObjectURL(blob)
const img = new Image()
img.src = objectURL
document.body.appendChild(img)
// what screw-filereader can do (auto rotate based on exif data)
// will resolve at img.onload event with a new img element
// will also cast a error if blob isn't a image (img.onerror)
// this is what you need...
blob.image().then(img => {
// convert image back to blob
var canvas = document.createElement('canvas')
canvas.width = img.width
canvas.height = img.height
const ctx = canvas.getContext('2d')
ctx.drawImage(img, 0, 0)
canvas.toBlob(uploadFiles)
// just to show the rotated image
document.body.appendChild(img)
})
})
function uploadFiles(blob) {
// upload blob
}
img {
width: 100px
}
<script src="https://cdn.jsdelivr.net/npm/screw-filereader@1.4.3/index.min.js"></script>
额外提示,请使用canvas.toBlob而不是使用dataURItoBlob