Question

我想在0到36之间生成37个数字。我想在水平列表中看到这些数字。

生成两次或更多次的数字必须显示在另一个水平列表中的列表下方。

有人可以帮助我吗？

到目前为止，我有这个：

<?php

    $numberOfSpins = 37;
    $numberArray = array();

    // Start table
    echo '<table><tr>';

    // print out the table headers
    for ($x = 0; $x < 37; $x++) echo '<th style="font-weight:bold; color:#09f;">'.$x.'</th>';

    // Fill $numberArray with random numbers
    for ($i = 0; $i < $numberOfSpins; $i++) 
        array_push($numberArray, mt_rand(0,36));

    echo '</tr><tr>';       

    // Count value frequency using PHP function array_count_value()
    $resultArray = array_count_values($numberArray);

    // Start from 0 since you are generating numbers from 0 to 36
    for ($i = 0; $i < 37; $i++)
    {
        // array_count_values() returns an associative array (the key of
        // each array item is the value it was counting and the value is the 
        // occurrence count; [key]->value).
        if (isset($resultArray[$i])) 
            echo '<td>'.$resultArray[$i].'</td>';
        else 
            echo '<td>0</td>';
    }

   echo '</tr></table>';
?>

Answer 1

尝试这种方式：

  //How many numbers the program will print 
  $cycles = 36; 

  //min random number
  $minNumber = 0;

  //Max random number
  $maxNumber = 37; 

  //all numbers
  $numbers = array();

  //repeated numbers
  $repeated_numbers = array();

  //repeated numbers string, th and td
  $r_numbers = "";
  $th = "";
  $td = "";
  for ($i=1; $i < $cycles + 1; $i++) { 
    //get a random number 
    $rand_n = rand($minNumber, $maxNumber);

    // create a td and th with the random number and the number index
    $td .= "<td> $rand_n </td>";
    $th .= "<th>Number $i </th>";

    //if the new random number is already on the number array means that is repeated
    // eif not, we store it in the all numbers array
    if (in_array($rand_n, $numbers))
        array_push($repeated_numbers, $rand_n);
    else
        array_push($numbers, $rand_n);
  }

  // we concat all the result to make a table and echo it out
  $table = "<table border='1'><thead>$th</thead><tbody>$td</tbody></table>";
  echo $table;

  //echo the repeated numbers only
  echo "<br> <br> <hr> Repeated Numbers = ";
  foreach ($repeated_numbers as $num) {
    echo "$num |";
  }

  echo "Total Repeated Numbers : " . count($repeated_numbers);

<强>更新

使用它来实现上述foreach以避免上一个|

  for ($i = 0; $i < count($repeated_numbers); $i++) {
    if ($i + 1 == count($repeated_numbers)) {
        echo "$repeated_numbers[$i]";
        continue;
    }
    echo "$repeated_numbers[$i] |";
  }

在php中生成0到36之间的37个数字

1 个答案: