Question

我正在尝试在子表'Contact'中插入Person的id。但是Hibernate在fk列存储值null。

我执行DTO到实体的映射，它已经带来了人的数据和联系人。最后，我必须保存人员实体。

有一个表继承！

父表：

@Entity
@Table
@Inheritance(strategy = InheritanceType.JOINED)
@DiscriminatorColumn(name = "type", discriminatorType = DiscriminatorType.STRING, columnDefinition = "CHAR(2)", length = 2)
public abstract class Person implements Serializable {

    @OneToMany(fetch = FetchType.EAGER, mappedBy = "person")
    @Cascade(value={org.hibernate.annotations.CascadeType.ALL})
    private @Getter @Setter Set<Contact> contacts;

}

表公司延伸人：

@Entity
@Table
@DiscriminatorValue(value="PJ")
public class Company extends Person implements Serializable {

    @Column(nullable = false, columnDefinition = "DATE")
    private @Getter @Setter LocalDate constitutionDate;

}

问题出在哪里！

@Entity
@Table(name = "contact")
@EqualsAndHashCode
public class Contact implements Serializable {
private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    private @Getter Integer id;

    @Column(columnDefinition = "VARCHAR(16)", length = 16, nullable = false)
    private @Getter @Setter String phoneNumber;

    @ManyToOne(fetch = FetchType.LAZY, optional = false,targetEntity=Person.class)
    @JoinColumn(name = "person_id", nullable = false, referencedColumnName="id")
    private @Getter @Setter Person person;

    public Contact() {}

    public Contact(String phoneNumber) {
        this.phoneNumber = phoneNumber;
    }
}

我做错了什么？什么是最好的策略？

对不起我的英语很差！

Answer 1

找不到任何明显的错误，但让我尝试一些事情：

您在Person类上的级联注释不需要特定的Hibernate枚举您可以使用如下：

@OneToMany(fetch = FetchType.LAZY, cascade = { CascadeType.ALL }, mappedBy = "cliente")

在Contact类的ManyToOne注释中，请尝试添加：

@ManyToOne(cascade = { CascadeType.PERSIST, CascadeType.MERGE })

Hibernate，Spring Data，在表child上插入表parent的id

1 个答案: