<project name="kernel/lk" path="bootable/bootloader/lk" revision="e48c9314142c2ae93619ccd14aba2bc975165ffd"/>
<Project name="device/google/contexthub" revision="c453c8b8fb25fb8e1c59e8288331a70dbff44061" />
我在文件中有两行。 我需要获取路径和修订版，如果路径在行中不可用，则必须将名称和修订版作为输出并保存在文件中
预期产出：
name="kernel/lk" , revision="e48c9314142c2ae93619ccd14aba2bc975165ffd"
path="device/google/contexthub" , revision="c453c8b8fb25fb8e1c59e8288331a70dbff44061"
如果有人给我代码片段，那将会很有帮助。
答案 0 :(得分：-1)
if（$ row = ~m / name =“（。+？）”\ spath =“（。+？）”\ srevision =“（。+？）”/ g）
{
打印“$ 1 $ 3 \ n”; onVerificationCompleted()
} PhoneAuthProvider.getInstance().verifyPhoneNumber(mobileNumber, 60, TimeUnit.SECONDS, FirebasePhoneAuthActivity.this, new PhoneAuthProvider.OnVerificationStateChangedCallbacks() {
@Override
public void onVerificationCompleted(PhoneAuthCredential phoneAuthCredential) {
smsCode = phoneAuthCredential.getSmsCode();
Log.i(TAG, "onVerificationCompleted: CODE " + smsCode);
Log.i(TAG, "onVerificationCompleted: PROVIDER " + phoneAuthCredential.getProvider());
}
@Override
public void onVerificationFailed(FirebaseException e) {
e.printStackTrace();
}
@Override
public void onCodeSent(String s, PhoneAuthProvider.ForceResendingToken forceResendingToken) {
Log.i(TAG, "onCodeSent: CODE " + s);
}
@Override
public void onCodeAutoRetrievalTimeOut(String s) {
super.onCodeAutoRetrievalTimeOut(s);
Log.i(TAG, "onCodeAutoRetrievalTimeOut: " + s);
}
});
elsif（$ row = ~m / name =“（。+？）”\ srevision =“（。+？）”/ g）
{test
打印“$ 1 $ 2 \ n”;
}
} enter code here