Question

我正在努力在Laravel中提出这个cURL请求

curl -d '{"key1":"value1", "key2":"value2"}' -H "Content-Type: application/json"   -X GET http://my.domain.com/test.php

我一直在尝试这个：

$endpoint = "http://my.domain.com/test.php";

$client = new \GuzzleHttp\Client();

$response = $client->post($endpoint, [
                GuzzleHttp\RequestOptions::JSON => ['key1' => $id, 'key2' => 'Test'],
            ]);

$statusCode = $response->getStatusCode();

但我收到错误Class 'App\Http\Controllers\GuzzleHttp\RequestOptions' not found

有什么建议吗？

修改

我需要在$response中获取API的响应，然后将其存储在DB中...我该怎么做？：/

Answer 1

尝试从Guzzle中获取查询选项：

$endpoint = "http://my.domain.com/test.php";
$client = new \GuzzleHttp\Client();
$id = 5;
$value = "ABC";

$response = $client->request('GET', $endpoint, ['query' => [
    'key1' => '$id', 
    'key2' => 'Test'
]]);

// url will be: http://my.domain.com/test.php?key1=5&key2=ABC;

$statusCode = $response->getStatusCode();
$content = $response->getBody();

// or when your server returns json
// $content = json_decode($response->getBody(), true);

我使用此选项用guzzle构建我的get-requests。结合json_decode（$ json_values，true），你可以将json转换为php数组。

Answer 2

如果您在使用guzzlehttp时遇到问题，仍然可以在PHP中使用本机cURL：

原生Php方式

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "SOME_URL_HERE".$method_request);
// SSL important
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);

$output = curl_exec($ch);
curl_close($ch);


$this - > response['response'] = json_decode($output);

有时这个解决方案比使用Laravel框架中附带的库更好更简单。但是，自从你掌握项目的开发以来，仍然是你的选择。

Answer 3

使用此作为参考。我已成功使用此代码生成curl GET请求

public function sendSms($mobile)
{
  $message ='Your message';
  $url = 'www.your-domain.com/api.php?to='.$mobile.'&text='.$message;

     $ch = curl_init();
     curl_setopt($ch, CURLOPT_URL, $url);
     curl_setopt($ch, CURLOPT_POST, 0);
     curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

     $response = curl_exec ($ch);
     $err = curl_error($ch);  //if you need
     curl_close ($ch);
     return $response;
}

Answer 4

使用Laravel，如果您使用的是WP并且感到冒险并且不想使用食人鱼或laravel curl包，则可以在route文件中编写类似的内容。

Route::get('/curl',function() {

$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, 'https://example.net/wp-login.php');

// save cookies to 'public/cookie.txt' you can change this later.
curl_setopt($ch, CURLOPT_COOKIEJAR, 'cookie.txt');

curl_setopt($ch, CURLOPT_POSTFIELDS, ['log'=>'<name>','pwd'=>'<pass>']);

curl_exec($ch);

// supply cookie with request
curl_setopt($ch, CURLOPT_COOKIE, 'cookie.txt');

// the url you would like to visit
curl_setopt($ch, CURLOPT_URL, 'https://example.net/profile/');

$content = curl_exec($ch);

curl_close($ch);

// webpage will be displayed in your browser
return;

});

Answer 5

您忘记在命名空间前添加\。

您应该写：

$response = $client->post($endpoint, [
                \GuzzleHttp\RequestOptions::JSON => ['key1' => $id, 'key2' => 'Test'],
            ]);

代替：

$response = $client->post($endpoint, [
                GuzzleHttp\RequestOptions::JSON => ['key1' => $id, 'key2' => 'Test'],
            ]);

laravel中的cURL请求

5 个答案: