Question

我有一个JSON对象，其中属性有点嵌套。我想在嵌套的JSON列表中插入一个数组，请参阅下面的代码以获取我的JSON对象。

JSON对象：

{
"companyId": 1,
"formation": "c",
"location": [{
    "landmark": "Coca Cola",
    "street1": "4104 Banner Rd",
    "type": "",
    "contact": []
}, {
    "landmark": "Pepsi",
    "street1": "4304 Commercial Rd",
    "type": "",
    "contact": []
}]

}

要插入的

联系数组是：

{
    "medium": "Office Phone",
    "serviceLocator": "800-285-3000",
    "prefered": "true",
    "locationRef": "Coca Cola"
}

我想做的就是这样：

在LOCATION中插入CONTACT，其中LOCATION.landmark等于＆＃34; Coca Cola＆＃34;

请指导我如何做到这一点，在我的AngularJS控制器中，我想尝试这样的事情，但是没有工作; AngularJS控制器：

$scope.company.location.contact.landmark["coca cola"].push({

    "medium": "Office Phone",
    "serviceLocator": "800-285-3000",
    "prefered": "true",
    "locationRef": "Coca Cola"

});

Answer 1

您可以使用foreach：

来完成此操作

$scope.company.location.forEach(loc => {
    if(loc.landmark === 'coca cola') {
        loc.contact.push({
            "medium": "Office Phone",
            "serviceLocator": "800-285-3000",
            "prefered": "true",
            "locationRef": "Coca Cola"
        });
    }
});

Answer 2

遍历位置数组并找到地标值等于“可口可乐”的索引。在该索引处插入联系人

for(var i=0; i<$scope.company.location.length; i++)
{
   if($scope.company.location[i].landmark=="Coca cola")
   {
      $scope.company.location[i].push(contact);
   }
}

Answer 3

您需要提及数组的索引

myArray.location[0].contact.push(contact);

编辑：

您可以使用 array.find() 然后推送到特定阵列！

<强>样本

＆＃13;

var myArray = {
"companyId": 1,
"formation": "c",
"location": [{
    "landmark": "Coca Cola",
    "street1": "4104 Banner Rd",
    "type": "",
    "contact": []
}, {
    "landmark": "Pepsi",
    "street1": "4304 Commercial Rd",
    "type": "",
    "contact": []
}]};

var contact = {
    "medium": "Office Phone",
    "serviceLocator": "800-285-3000",
    "prefered": "true",
    "locationRef": "Coca Cola"
};
var result = myArray.location.find(t=>t.landmark ==='Coca Cola');

result.contact.push(contact);

console.log(result);

＆＃13;

如何通过AngularJS控制器在嵌套的JSON属性中插入数组

3 个答案: