Question

使用Rails的ActiveRecord在以下JSON代码段中将两个子地址记录存储在父货件记录下的最佳方法是什么？

显然，存储子记录的标准方法是配置普通的has_many - belongs_to关系，但在这种情况下，父记录“有两个”子记录，我认为不合适，加上has_many - belongs_to关系不允许将一个记录定位到另一个记录上的方式相同（即：shipment.to_address不会“不行”

非常感谢任何帮助。

由于

{
  "id": "shp_vN9h7XLn",
  "to_address": {
    "id": "adr_zMlCRtmt",
    "name": "Dr. Joe Bloggs",
    "company": null,
    "street1": "323 Some Dr",
    "street2": null,
    "city": "Example City",
    "state": "XX",
    "zip": "00000",
    "country": "XX",
    "phone": "0000000000",
    "email": "example@example.com",
    "created_at": "2013-04-22T05:39:56Z",
    "updated_at": "2013-04-22T05:39:56Z"
  },
  "from_address": {
    "id": "adr_VgoLT6Ex",
    "name": "Some Rep",
    "company": "Example Co.",
    "street1": "43 Example St",
    "street2": null,
    "city": "Example City",
    "state": "XX",
    "zip": "00000",
    "country": "XX",
    "phone": "0000000000",
    "email": "support@example.com",
    "created_at": "2013-04-22T05:39:57Z",
    "updated_at": "2013-04-22T05:39:57Z"
  },
  "tracking_code": null,
  "refund_status": null,
  "created_at": "2013-04-22T05:40:57Z",
  "updated_at": "2013-04-22T05:40:57Z"
}

Answer 1

IMO，您的2个地址不同，一个适用于from_address，另一个适用于to_address

货件有一个 from_adress
货件有一个 to_adress
from_address和to_address都只是地址。

因此，您可以使用Rails的STI（单表继承）功能来解决此问题。我想您熟悉STI，所以只需提供最终代码

class Shipment < ActiveRecord::Base
  has_one :from_address, class_name: Address::FromAddress.name
  has_one :to_address, class_name: Address::ToAddress.name
  # Blah blah
end

要成为明确的定义，您甚至可以毫无顾虑地为一批货物存储多个to_adress。

有关详细信息，请阅读Rails's Guide # Single Table Inheritance

存储可定位子记录的最佳方法 - ActiveRecord |轨道

1 个答案: