Question

我有这个数组，我必须将对象推入数组。但现在我试图摆脱'cahlan'的整个对象。底部的for循环是我尝试过但它似乎不起作用。

var employees = [];

var tyler = {
  name: 'Tyler',
  position: 'Lead Instructor/Engineer',
  spiritAnimal: 'Honey Badger'
};

var cahlan = {
  name: 'Cahlan',
  position: 'CEO',
  spiritAnimal: 'butterfly'
};

var ryan = {
  name: 'Ryan',
  position: 'Marketing',
  spiritAnimal: 'fox'
};

var colt = {
  name: 'Colt',
  position: 'Everything really',
  spiritAnimal: 'Young Male Horse'
};

employees.push("tyler", "cahlan", "ryan", "colt");

for (var i = 0; i < employees.length; i++) {
  if (employees[i].name === "Cahlan") {
    employees.splice(i);
  }
}

Answer 1

＆＃13;

var employees = [];

employees.push("tyler", "cahlan", "ryan", "colt");

for (var i = 0; i < employees.length; i++) {
  if (employees[i] === "cahlan") {
     employees.splice(i, 1);
     break;
  }
}

console.log(employees)

＆＃13;

两件事：

您正在使用大写单词Cahlan进行比较。
employees数组中的对象是字符串，因此attr name不存在。

可能你没有意识到，但是你没有添加你已经初始化的对象，因此，数组正在用字符串进行初始化。

Answer 2

你的解决方案正朝着正确的方向前进，但你犯了两个错误。

首先

employees.push("tyler", "cahlan", "ryan", "colt");

不会按预期将数组推送到数组中。它将字符串推送到employees，它只包含对象的变量名称。 JavaScript并不知道您正在尝试引用这些对象。它认为你只是创建一些文本。要做到正确，请删除双引号：

employees.push(tyler, cahlan, ryan, colt);

您可以随时通过将数组打印到控制台来检查数组的内容：

console.log(employees);

其次，您需要将第二个参数传递给splice，它告诉它要从数组中删除多少项。由于您只想删除一个项目，请执行以下操作：

employees.splice(i, 1);

完整解决方案：

＆＃13;

var employees = [];

var tyler = {
  name: 'Tyler',
  position: 'Lead Instructor/Engineer',
  spiritAnimal: 'Honey Badger'
};

var cahlan = {
  name: 'Cahlan',
  position: 'CEO',
  spiritAnimal: 'butterfly'
};

var ryan = {
  name: 'Ryan',
  position: 'Marketing',
  spiritAnimal: 'fox'
};

var colt = {
  name: 'Colt',
  position: 'Everything really',
  spiritAnimal: 'Young Male Horse'
};

employees.push(tyler, cahlan, ryan, colt); // 1.) remove double quotes

console.log(employees); // print array to console to check if array is setup right

for (var i = 0; i < employees.length; i++) {
  if (employees[i].name === "Cahlan") {
    employees.splice(i, 1); // 2.) add second paramter
  }
}

console.log(employees); // print array again to see if removing worked

＆＃13;

Answer 3

普通javascript：

var ret = [];

for (var i = 0; i < employees.length; i++) {
  if (employees[i].name !== "Cahlan") ret.push(employees[i]);
}

//ret has the employees with Cahlan removed.

使用Jquery：

employees = $.grep(employees, function(a)) {
  return a.name !== "Cahlan";
});

你应该先做更多的搜索。见remove-object-from-array-using-javascript

Answer 4

我只是想我可以通过properly working with objects

教你如何钓鱼

如果您可以控制创建/声明，只需做正确的事情并正确构建对象

var employees = [
{
  name: 'Tyler',
  position: 'Lead Instructor/Engineer',
  spiritAnimal: 'Honey Badger'
 },
{
  name: 'Tyler',
  position: 'Lead Instructor/Engineer',
  spiritAnimal: 'Honey Badger'
},
{
  name: 'Cahlan',
  position: 'CEO',
  spiritAnimal: 'butterfly'
},
{
  name: 'Ryan',
  position: 'Marketing',
  spiritAnimal: 'fox'
},
{
  name: 'Colt',
  position: 'Everything really',
  spiritAnimal: 'Young Male Horse'
}];

如果你不这样做，我建议你结束：

var obj = Object.assign({}, tyler, cahlan, ryan, colt);

将等于上面的完整对象，

现在有几种方法可以从ARRAY中添加OMITTING对象，有些方法是删除，在上面正确建议的循环中跳过。

你可以试试lodash _.omit, _.concat等麻烦

//1
employees.shift(); // first element removed
//2
employees= employees.slice(1); // first element removed
//3
employees.splice(0,1); // first element removed
//4
employees.pop(); // last element removed
// 5 return everything but Cahlan
employees.filter(function(arr) { return arr.name !== "Cahlan"; }); 
// 5 return only Cahlan
employees.filter(function(arr) { return arr.name === "Cahlan"; });

Answer 5

首先，使用

employees.push(tyler,cahlan,ryan,colt)

没有" "

然后...

employYouWant = employees.filter( (employ) => employ.name === 'Cahlan')///{name: 'Cahlan', position: 'CEO', spiritAnimal: 'butterfly'};

Answer 6

""是一个String，{}是一个Object literal
因此employees.push("tyler", "cahlan", "ryan", "colt");正在推动......♪弦乐。

将此修复后 - 推送您的实际对象文字：

employees.push(tyler, cahlan, ryan, colt);

您最终可以访问对象的.name属性你可以 .filter（）你的阵列：

var employees = [];

var tyler = {
  name: 'Tyler',
  position: 'Lead Instructor/Engineer',
  spiritAnimal: 'Honey Badger'
};

var cahlan = {
  name: 'Cahlan',
  position: 'CEO',
  spiritAnimal: 'butterfly'
};

var ryan = {
  name: 'Ryan',
  position: 'Marketing',
  spiritAnimal: 'fox'
};

var colt = {
  name: 'Colt',
  position: 'Everything really',
  spiritAnimal: 'Young Male Horse'
};

employees.push(tyler, cahlan, ryan, colt); // Push your actual Object literals

employees = employees.filter( obj => obj.name !== "Cahlan" );

console.log( employees )

请参阅此更具功能性的方法来过滤您的阵列。您可以使用辅助函数来管理员工数组：

let employees = [];

const addEmployee = (name, position, spiritAnimal) =>
  employees.push({name, position, spiritAnimal});

const removeEmployee = (name) =>
  employees = employees.filter( obj => obj.name !== name );

// Let's add some to Array
addEmployee('Tyler', 'Lead Instructor/Engineer', 'Honey Badger');
addEmployee('Cahlan', 'CEO', 'butterfly');
addEmployee('Ryan', 'Marketing', 'fox');
addEmployee('Colt', 'Everything really', 'Young Male Horse');

// Let's remove some from Array
removeEmployee('Cahlan');
removeEmployee('Colt');

console.log( employees );

或者你可以用更通用的 Prototypal 或 Class -y方式和数组不可知的方式重写上述内容。

如何从数组中删除对象？

6 个答案:

如果您可以控制创建/声明，只需做正确的事情并正确构建对象

如果你不这样做，我建议你结束：