在foreach中排除空类别名称（$ category作为$ category）

Question

我用以下代码行回显一个类别列表。不幸的是，foreach($categories as $category) {...部分还列出了没有帖子的类别。知道如何使用相同的结构排除空类别吗？

<?php $categories = get_categories('exclude=' . implode(',', test_blog_cats()) . ', 1'); ?>

<?php if (!isset($_GET['category'])) {  
    echo '<li><a class="popular-categories icon-caret-left" href="' . get_permalink() . '">' . __('All Categories', 'test') . '</a></li>';                              
} else {
    echo '<li><a class="popular-categories" href="' . get_permalink() . '">' . __('All Categories', 'test') . '</a></li>';                                                           
?>

<?php foreach($categories as $category) { ?>
    <li>
        <a class="popular-categories<?php if (isset($_GET['category']) && $_GET['category'] == $category->category_nicename) echo ' icon-caret-left bodycolor'; ?>" href="<?php echo get_permalink(); ?>?category=<?php echo $category->category_nicename; ?>"><?php echo $category->name; ?>&nbsp;</a> 
    </li>
<?php } ?>

Answer 1

以下对我来说很好......

＆＃13;

＆＃13;

<?php
// Check ALL categories for posts of given post type
$categories = get_categories();

// the below will only list categories with one or more post
foreach($categories as $category) {
    echo '<li><a href="' . get_category_link($category->term_id) . '">' . $category->name . '</a></li>';
}
?>

＆＃13;

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