Question

为什么此代码的输出是：

抽屉一场胜利一场胜利 ERROR

而不是

抽屉一场胜利 ERROR
ERROR

应该是什么？

为什么break不起作用，并且不为strB中不允许使用字母“T”的字符串给出结果='ERROR'？（strB ='SRTR'）

def RockPaperScissors(strA,strB):
    A_win = 0
    B_win = 0
    allowed_letters = 'SRP'

    if (len(strA) != len(strB)):
        result = 'ERROR'

    elif (len(strA) == len(strB)):

        for char in strA:
            for c in strB:
                if char not in allowed_letters:
                    result = 'ERROR'
                    break
                elif c not in allowed_letters:
                    result = 'ERROR'
                    break

        for i in range(0,len(strA)):
            if (strA[i] == 'R' and strB[i] == 'S'):
                a_win = 1
                A_win += a_win
            if (strA[i] == 'S' and strB[i] == 'P'):
                a_win = 1
                A_win += a_win
            if (strA[i] == 'P' and strB[i] == 'R'):
                a_win = 1
                A_win += a_win
            if (strB[i] == 'R' and strA[i] == 'S'):
                b_win = 1
                B_win += b_win
            if (strB[i] == 'S' and strA[i] == 'P'):
                b_win = 1
                B_win += b_win
            if (strB[i] == 'P' and strA[i] == 'R'):
                b_win = 1
                B_win += b_win   

        if A_win > B_win:
            result = 'A WINS'
        if B_win > A_win:
            result = 'B WINS'
        if A_win == B_win:
            result = 'DRAW'

    return result

print(RockPaperScissors('RP','PR'))
print(RockPaperScissors('PPP','RRR'))
print(RockPaperScissors('RPSR','SRTR'))
print(RockPaperScissors('RPS','RPSRP'))

Answer 1

Break仅打破当前循环。你想做的不是打破，而是直接返回错误。

for char in strA:
    for c in strB:
        if char not in allowed_letters:
            return 'ERROR'
        elif c not in allowed_letters:
            return 'ERROR'

打破for语句循环

1 个答案: