Question

我有使用Ajax填充数据表的javascript函数。我的javascript代码如下：

 $('#results').dataTable({
    // Ajax load data
    "ajax": {
        "url": "get_intl_tickets",
        "type": "POST",
        "data": {
            "user_id": 451,
            "csrfmiddlewaretoken" : csrftoken,
        }
    }
 })

我在django中的服务器端脚本有一个加载大约500个数据行的函数。现在的问题是我不想一次加载整个数据。相反，我希望有前10个数据行。然后用分页，另外10行像那样。我阅读了数据表的server side processing页面文档。我也尝试使用"serverSide": true选项。我不了解服务器端脚本。给出了PHP的一个例子。似乎他们没有使用draw, recordsFiltered, recordsTotal之类的任何参数。他们在那里使用了php SSP类。它不知道它做了什么。我正试图在django中实现它。

但我没有找到适当的好文档来实现。任何帮助将不胜感激。

Answer 1

老问题，但我也出奇地难以找到答案，所以万一其他人最终来到这里......：P

我发现这篇 2020 年的文章非常有帮助，特别是第 6 部分展示了“完整代码”，其中包括获取正确的变量、构建 SQL 查询以及如何构建/构造它响应的数据对象： https://makitweb.com/datatables-ajax-pagination-with-search-and-sort-php/

他们的例子贴在下面：

<?php
## Database configuration
include 'config.php';

## Read value
$draw = $_POST['draw'];
$row = $_POST['start'];
$rowperpage = $_POST['length']; // Rows display per page
$columnIndex = $_POST['order'][0]['column']; // Column index
$columnName = $_POST['columns'][$columnIndex]['data']; // Column name
$columnSortOrder = $_POST['order'][0]['dir']; // asc or desc
$searchValue = mysqli_real_escape_string($con,$_POST['search']['value']); // Search value

## Search 
$searchQuery = " ";
if($searchValue != ''){
   $searchQuery = " and (emp_name like '%".$searchValue."%' or 
        email like '%".$searchValue."%' or 
        city like'%".$searchValue."%' ) ";
}

## Total number of records without filtering
$sel = mysqli_query($con,"select count(*) as allcount from employee");
$records = mysqli_fetch_assoc($sel);
$totalRecords = $records['allcount'];

## Total number of record with filtering
$sel = mysqli_query($con,"select count(*) as allcount from employee WHERE 1 ".$searchQuery);
$records = mysqli_fetch_assoc($sel);
$totalRecordwithFilter = $records['allcount'];

## Fetch records
$empQuery = "select * from employee WHERE 1 ".$searchQuery." order by ".$columnName." ".$columnSortOrder." limit ".$row.",".$rowperpage;
$empRecords = mysqli_query($con, $empQuery);
$data = array();

while ($row = mysqli_fetch_assoc($empRecords)) {
   $data[] = array( 
      "emp_name"=>$row['emp_name'],
      "email"=>$row['email'],
      "gender"=>$row['gender'],
      "salary"=>$row['salary'],
      "city"=>$row['city']
   );
}

## Response
$response = array(
  "draw" => intval($draw),
  "iTotalRecords" => $totalRecords,
  "iTotalDisplayRecords" => $totalRecordwithFilter,
  "aaData" => $data
);

echo json_encode($response);

Answer 2

很好的例子： https://datatables.net/examples/server_side/defer_loading.html

但是你需要编辑服务器端。响应演示

{ 得出：2， recordsFiltered：57， recordsTotal：57 }

基于ajax的分页的jquery数据表

2 个答案: