我有一个JSON
对象,其中包含名称和值列表。我想与另一个数组[String]
进行比较,如果在JSON
对象值之一中找到该值,则将该值合并到一个新对象。
我尝试在merge(with)
循环中使用for
但是,它似乎只合并了一个值。
> example: > > json_cat = > > { > name: "aaa", > surname: "aaa-1", > grade: "aaa-2" > }, > { > name: "bbb", > surname: "bbb-1", > grade: "bbb-2" > }, > { > name: "ccc", > surname: "ccc-1", > grade: "ccc-2" > } > // > let arraytest:[String] = ["aaa", "ccc", "ddd"] > // array json_cat compare arraytest > result = { > name: "aaa", > surname: "aaa-1", > grade: "aaa-2" > }, > { > name: "ccc", > surname: "ccc-1", > grade: "ccc-2" > }
let json_cat: JSON = "json from url"
let arraytest:[String] = ["aaa", "ccc", "ddd"]
var json_cat_array = JSON()
json_cat.forEach({ (index, json_p) in
if arraytest.contains(json_p["name"].string!) {
//print("\(index) - \(json_p)")
try! json_cat_array.merge(with: json_p)
}
})
答案 0 :(得分:0)
此代码使用Swift 4基础JSON解析器。 Swift 4默认情况下有一个奇怪的解析器。
import Foundation
let jsonString = """
[{
"surname": "Roxxy",
"grade": "neaou"
},
{
"name": "Puffi",
"surname": "Chips",
"grade": "meaou"
},
{
"name": "Taffy",
"surname": "Baby",
"grade": "mew-mew"
}]
"""
struct JsonCat: Decodable {
let name: String?
let surname: String
let grade: String
}
struct Cat {
let name: String
let surname: String
let grade: String
}
guard let jsonData = jsonString.data(using: .utf8), let jsonCats = try? JSONDecoder().decode([JsonCat].self, from: jsonData) else {
fatalError()
}
var cats: [Cat] = []
jsonCats.forEach { jsonCat in
guard let name = jsonCat.name else {
return
}
let cat = Cat(name: name, surname: jsonCat.surname, grade: jsonCat.grade)
cats.append(cat)
}
print(cats)
答案 1 :(得分:0)
你可以像这样实现你的循环:
json_cat.forEach({ (index, json_p) in
if arraytest.contains(json_p["name"].string!) {
//print("\(index) - \(json_p)")
json_cat_array[json_p["name"].string!] = json_p
}
})
合并功能实际上是用于合并数据。就像在这个例子中一样:
let original: JSON = [
"first_name": "John",
"age": 20,
"skills": ["Coding", "Reading"],
"address": [
"street": "Front St",
"zip": "12345",
]
]
let update: JSON = [
"last_name": "Doe",
"age": 21,
"skills": ["Writing"],
"address": [
"zip": "12342",
"city": "New York City"
]
]
let updated = original.merge(with: update)
// [
// "first_name": "John",
// "last_name": "Doe",
// "age": 21,
// "skills": ["Coding", "Reading", "Writing"],
// "address": [
// "street": "Front St",
// "zip": "12342",
// "city": "New York City"
// ]
// ]