Question

我一直在尝试研究如何在django中创建编辑视图，但我尝试的所有内容都会失败而不能让我能够编辑已保存的对象。问题会很好地创建并保存和显示但我只是无法加载它们进行编辑。代码如下所示，任何帮助或建议都会很好。

views.py

class FormView(FormView):
    template_name = 'issuetracker/form.html'
    form_class = CreateIssueForm
    success_url = '/issue/'

    def form_valid(self, form):
        obj = Issue.objects.create(
            submitter=form.cleaned_data.get('submitter'),
            description=form.cleaned_data.get('description'),
            status=form.cleaned_data['status'],
            category=form.cleaned_data.get('category'),
        )
        return super().form_valid(form)


class IssueUpdateView(UpdateView):

    context_object_name = 'issue-update'
    form_class = CreateIssueForm
    template_name = 'issuetracker/update.html'
    success_url = 'issuetracker/issue_list.html'

    # get object
    def get_object(self):
        return self.request.user

    # override form_valid method
    def form_valid(self, form):
        # save cleaned post data
        clean = form.cleaned_data
        context = {}
        self.object = context.save(clean)
        return super(IssueUpdateView, self).form_valid(form)

forms.py

class CreateIssueForm(forms.ModelForm):
    STATUS = (
        ('Assigned', 'Assigned'),
        ('Closed', 'Closed'),
    )
    CATEGORY = (
        ('Bug', 'Bug'),
        ('Enhancements', 'Enhancements'),
        ('Documentation', 'Documentation')
    )

    submitter = forms.CharField(required=False)
    solver = forms.CharField(required=False)
    description = forms.CharField(widget=forms.Textarea,required=False)
    status = forms.ChoiceField(required=False,choices=STATUS)
    category = forms.ChoiceField(required=False,choices=CATEGORY)


        class Meta:
            model = Issue
            fields = ('submitter', 'solver', 'description','status','category')

models.py

class Issue(models.Model):
    STATUS = (
    ('A', 'Assigned'),
    ('C', 'Closed'),
    )
    CATEGORY = (
        ('B', 'Bug'),
        ('E', 'Enhancements'),
        ('D', 'Documentation')
    )
    submitter = models.CharField(max_length=30)
    solver = models.CharField(max_length=30, null=True, blank=True)
    description = models.CharField(max_length=500)
    status = models.CharField(max_length=1, choices=STATUS)
    category = models.CharField(max_length=1, choices=CATEGORY)
    opened = models.DateTimeField(auto_now_add=True)
    updated = models.DateTimeField(auto_now=True)

    def __str__(self):
        return self.description

urls.py

url(r'^$', StatView.as_view(), name='stat_view'),
url(r'^(?P<slug>\w+)/$', IssueListView.as_view()),
url(r'^/create/$', FormView.as_view(), name='create_issue'),
url(regex=r'^issues/edit$',
    view= IssueUpdateView.as_view(),
    name='issue-update')

Answer 1

下面：

class IssueUpdateView(UpdateView):
    # ...
    def get_object(self):
        return self.request.user

我不知道你为什么要回到这里request.user（这可能是你完全不了解的一些例子的复制粘贴吗？） - 但无论如何： UpdateView.get_object()应该返回要编辑的对象。您通常从一个从url到视图的参数传递的唯一ID中获取此对象：

url(regex=r'^issues/edit/(?P<issue_id>\d+)/$',
    view= IssueUpdateView.as_view(),
    name='issue-update')



class IssueUpdateView(UpdateView):
    # ...
    def get_object(self, queryset=None):
        return Issue.objects.get(id=self.kwargs["issue_id"])

在django中创建编辑视图以修改现有问题

1 个答案: