这是MySQL和UUID
类型的id特有的,我正在使用MySQL本身的uuid()
函数。它不会为resultSet
提供空值,但next()
值始终为空。
以下是代码:
String insertQuery = "INSERT INTO fixtures "
+ "(id, whatever1, whatever2, whatever3, whatever4, "
...
+ "created_at) "
+ "VALUES(UUID(), ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
PreparedStatement preparedStatement = connection.prepareStatement(insertQuery, Statement.RETURN_GENERATED_KEYS);
.
.
.
preparedStatement.setDate(23, sqlDate);
preparedStatement.executeUpdate();
ResultSet keysResultSet = preparedStatement.getGeneratedKeys();
System.out.println(keysResultSet); // com.mysql.cj.jdbc.result.ResultSetImpl@6892b3b6
if(keysResultSet != null && keysResultSet.next()){
System.out.println("Generated Emp Id: "+keysResultSet.getString("id"));
} else {
System.out.println("No KEYS GENERATED");
}
答案 0 :(得分:1)
没有生成密钥,但实际提供了:
所以要么将创建留给数据库:
String insertQuery = "INSERT INTO fixtures "
+ "(whatever1, whatever2, whatever3, whatever4, "
...
+ "created_at) "
+ "VALUES(?, ?, ?, ?, ?, ?, ?, ?, ?, "
+ "?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
由于我不知道如何在MySQL端轻松实现UUID,我建议使用java端的UUID原始解决方案:
String insertQuery = "INSERT INTO fixtures "
+ "(id, whatever1, whatever2, whatever3, whatever4, "
...
+ "created_at) "
+ "VALUES(?, ?, ?, ?, ?, ?, ?, ?, "
+ "?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
UUID id = UUID.randomUUID();
preparedStatement.setString(1, id.toString());
获取UUID然后变得无关紧要。
答案 1 :(得分:0)
对于SQL Server 2008和更高版本,您可以使用自动生成的UUID定义主键。要检索INSERT语句生成的UUID,请在列定义之后添加OUTPUT选项,然后将statement.executeUpdate替换为statement.executeQuery并从ResultSet中检索值。这是显示如何执行此操作的代码片段:
sqlStmt.append("INSERT INTO tableName");
sqlStmt.append(" (column1");
sqlStmt.append(", column2");
...
sqlStmt.append(" OUTPUT inserted.columnUUID");
sqlStmt.append(" VALUES (?, ?, ?, ?) ");
statement = connection.prepareStatement(sqlStmt.toString());
statement.clearParameters();
int index = 0;
ResultSet resultSet = statement.executeQuery();
if (resultSet.next())
{
result = resultSet.getString(1);
companyDB.varUUID = result;
}
答案 2 :(得分:0)
Jop Eggan的答案解决了这个问题。但是,如果该方法出现任何错误,您也可以执行以下操作:
String insertQuery = "INSERT INTO fixtures "
+ "(id, whatever1, whatever2, whatever3, whatever4, "
...
+ "created_at) "
+ "VALUES(?, ?, ?, ?, ?, ?, ?, ?, "
+ "?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
UUID id = UUID.randomUUID();
preparedStatement.setObject(1, id);