我有这个代码,我从多输入文件类型
循环到文件
$(function(){
$('#main-input').change(function(){
var files = $('#main-input')[0].files;
for (var i = 0, f; f = files[i]; i++) {
alert(files[i].name);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="file" id="main-input" multiple>
我想要实现的是克隆主输入(#main-input)并根据循环文件给出一个值(文件)。有什么想法,建议吗?或者这甚至可能吗?
答案 0 :(得分:4)
是的,要求是可能的。您需要为每个FileList
对象创建一个新的File
,然后将.files
元素的<input type="file">
属性设置为FileList
,其中填充{{1}对象。
下面的代码在Chromium 62+和Firefox 57+上返回相同的结果,请参阅@Kaiido对Safari和Edge的评估的评论。
File
// FileList.js
class FileList {
constructor(...items) {
// flatten rest parameter
items = [].concat(...items);
// check if every element of array is an instance of `File`
if (items.length && !items.every(file => file instanceof File)) {
throw new TypeError("expected argument to FileList is File or array of File objects");
}
// use `ClipboardEvent("").clipboardData` for Firefox, which returns `null` at Chromium
// we just need the `DataTransfer` instance referenced by `.clipboardData`
const dt = new ClipboardEvent("").clipboardData || new DataTransfer();
// add `File` objects to `DataTransfer` `.items`
for (let file of items) {
dt.items.add(file)
}
return dt.files;
}
}
document.querySelector("input[type=file]")
.onchange = e => {
for (let file of e.target.files) {
const input = document.createElement("input");
input.type = "file";
input.files = new FileList(file);
document.body.appendChild(input);
}
}
<input type="file" multiple>
// FileList.js
function _FileList(items) {
// flatten rest parameter
items = [].concat.apply([], [items]);
// check if every element of array is an instance of `File`
if (items.length
&& !items.every(function(file) {
return file instanceof File})) {
throw new TypeError("expected argument to FileList is File or array of File objects");
}
// use `ClipboardEvent("").clipboardData` for Firefox, which returns `null` at Chromium
// we just need the `DataTransfer` instance referenced by `.clipboardData`
var dt = new ClipboardEvent("").clipboardData || new DataTransfer();
// add `File` objects to `DataTransfer` `.items`
for (var i = 0; i < items.length; i++) {
dt.items.add(items[i])
}
return dt.files;
}
document.querySelector("input[type=file]")
.onchange = function(e) {
for (var i = 0; i < e.target.files.length; i++) {
var input = document.createElement("input");
input.type = "file";
input.files = new _FileList(e.target.files[i]);
document.body.appendChild(input);
}
}