Question

我无法弄清楚如何在PHP / MySql中显示此查询的结果。如果可能，我想使用准备好的声明。

SELECT count( DISTINCT(video_view_ip) ) FROM video_views

Answer 1

从sql获取数据并使用php打印它请使用这种方式

首先连接到数据库

                $con = mysqli_connect("localhost","username","password");
                if (!$con)
                {
                     die('Could not connect: ' . mysql_error());
                }
                mysqli_select_db($con,"db_name");

并在连接后，从表中检索数据

                $sql_fetch_vide_count = "SELECT count( DISTINCT(video_view_ip) ) as video_count FROM video_views ";
                $video_result = $con->query($sql_fetch_vide_count);
                if (!$video_result) {
                    die('Could not enter data: ' . mysql_error());
                }

                //getting the date to array
                $row_video = $video_result->fetch_assoc();

                //Fetch the count result
                $video_count = isset($row_video ['video_count ']) ? $row_video ['video_count '] : 0;

如果从数据库中提取所有数据，请使用

                $array_videos = array();
                while ($row_video = $video_result->fetch_assoc()) {
                    $array_videos [] = $row_video ;
                }

您可以将所有数据作为数组存入$ array_videos

Answer 2

首先，我们需要获取与数据库的连接。为此，我们将使用PDO：

<?php

$config = [
  'driver'   => 'mysql',
  'host'     => 'localhost',     // replace this with the actual mysql host if needed
  'port'     => 3306,            // default mysql port is 3306
  'database' => 'my_database',   // replace this with the database you are using
  'username' => 'admin',         // replace this with your username
  'password' => 'password',      // replace this with your password
];

$connection = new PDO(
  vsprintf('%s:Server=%s,%s;Database=%s', [
    $config['driver'],
    $config['host'],
    $config['port'],
    $config['database'],
  ]),
  $config['username'],
  $config['password']
);

要将配置保密，您可以将其存储在一个单独的只读文件中。然后，您可以使用parse_ini_file阅读此配置。

要运行查询并存储结果，我们必须执行以下操作：

// in this case, we can use fetchColumn to retrieve the count, since it is a single value. However, we will usually want to use fetch() for most cases.
$count = $connection
  ->query('SELECT count( DISTINCT(video_view_ip) ) FROM video_views')
  ->fetchColumn();

要显示结果，我们只需echo将其显示出来：

echo $count;

Answer 3

检查这个例子，了解如何在php页面上生成输出已编辑：在OP请求之前添加准备好的声明

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);

// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

// prepare and bind
$stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname, email) VALUES (?, ?, ?)");
$stmt->bind_param("sss", $firstname, $lastname, $email);

// set parameters and execute
$firstname = "John";
$lastname = "Doe";
$email = "john@example.com";
$stmt->execute();

$firstname = "Mary";
$lastname = "Moe";
$email = "mary@example.com";
$stmt->execute();

$firstname = "Julie";
$lastname = "Dooley";
$email = "julie@example.com";
$stmt->execute();

echo "New records created successfully";

$stmt->close();
$conn->close();
?>

如何使用PHP显示此SQL的结果

3 个答案: