Question

我想处理以我不需要的对象开始的JSON数据。

这里有URL：

http://datos.santander.es/api/rest/datasets/callejero_calles.json?items=819

我一直在努力调整下一个代码，但我不知道如何避开第一个对象（摘要）并采取第二个（资源）。

如果我想逐个采取来自＆＃34;资源＆＃34;的每个对象内的所有数据。（例如，显示＆＃34; nombre-calle＆＃34;，＆＃34; tipo-via＆＃34; ...）。

package leerjson;

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;

public class LeerJSON {

    public static void main(String[] args) throws ParseException {
        JSONParser parser = new JSONParser();

        try {        
            URL oracle = new URL("http://datos.santander.es/api/rest/datasets/callejero_calles.json?items=819"); // URL to Parse
            URLConnection yc = oracle.openConnection();
            BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream()));

            String inputLine; 
            in.readLine();
            while ((inputLine = in.readLine()) != null) {   
                JSONArray a = (JSONArray) parser.parse(inputLine);

                // Loop through each item
                for (Object o : a) {
                    JSONObject datos = (JSONObject) o;
                    System.out.println(datos);
                }
            }
            in.close();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } catch (ParseException e) {
            e.printStackTrace();
        }  
    }

更新：一旦看到Enra64的回答，我就不知道如何使用getJSONArray和getJSONObject，因为它不是一种方法。我已将json-simple-1.1.1.jar包含在我的项目中，但它不起作用。先感谢您！这是我的新代码：

URL oracle = new URL("http://datos.santander.es/api/rest/datasets/callejero_calles.json?items=819"); // URL to Parse
   URLConnection yc = oracle.openConnection();
   BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream()));

   String inputLine = in.readLine();

   JSONObject a = (JSONObject) parser.parse(inputLine);
   JSONArray resources = a.getJSONArray("resources");

   for (int i = 0; i < resources.length(); i++) {
        resources.getJSONObject(i);
   }

Answer 1

选择资源对象，如下所示：

for (int i = 0; i < resources.length(); i++) {
  resources.getJSONObject(i);
}

然后循环播放：

@RELATION data_weka

@ATTRIBUTE class {1,0}

@ATTRIBUTE 1 NUMERIC
        .
        .
        .
@ATTRIBUTE 30 NUMERIC

@DATA

1,17.99,10.38,122.8,1001,0.1184,0.2776,0.3001,0.1471,0.2419,0.07871,1.095,0.9053,8.589,153.4,0.006399,0.04904,0.05373,0.01587,0.03003,0.006193,25.38,17.33,184.6,2019,0.1622,0.6656,0.7119,0.2654,0.4601,0.1189
             . 
             . 
             .

从以不必要数据开头的URL读取Java中的JSON

1 个答案: